'Du 2x dx' presentation slideshows

By Dr. Safa Ahmed El- Askary Faculty of Allied Medical of Sciences

Lecture (7&8) Integration by Parts. By Dr. Safa Ahmed El- Askary Faculty of Allied Medical of Sciences. Integration by parts. Product Rule:. Integration by parts. Let dv be the most complicated part of the original integrand that fits a basic integration

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Section 4.3

Section 4.3. Let u = x 2 +1. Then du = 2x dx and the integral becomes. And reversing the substitution yields:. ? e u du = e u + C. Let u = x 5 . Then du = 5x 4 dx and the integral becomes. And reversing the substitution yields:.

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Integration by parts

Integration by parts. Product Rule:. Integration by parts. Let dv be the most complicated part of the original integrand that fits a basic integration Rule (including dx ). Then u will be the remaining factors. OR. Let u be a portion of the integrand whose

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5.7 Inverse Trigonometric Functions: Integration and Completing the Square

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5.4 Exponential Functions: Differentiation and Integration

5.4 Exponential Functions: Differentiation and Integration. The inverse of f(x) = ln x is f -1 = e x. Therefore, ln (e x ) = x and e ln x = x. Solve for x in the following equations. Take the ln of both sides. Operations with Exponential Functions.

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6.3 Separation of Variables and the Logistic Equation

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6.3 Separation of Variables and the Logistic Equation

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