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2 plot w1 pi - PowerPoint PPT Presentation

>> n=-50:50; wc=0.4pi; >> hn=sinc(nwc/pi)*wc/pi;

>> n=-50:50; wc=0.4*pi; >> hn=sinc(n*wc/pi)*wc/pi; >> stem(n,hn); title('Ideal LPF with cutoff frequency = 0.4 pi'). >> w=linspace(0,pi,512); mag_hw= cos (w/2); >> [h,w1]=freqz([0.5 0.5],[1]); >> subplot(2,1,1); plot(w/pi,mag_hw);title('|H(omega)|of first order FIR LPF:analytical solution')

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2 plot w1 pi - PowerPoint PPT Presentation

&gt;&gt; n=-50:50; wc=0.4*pi; &gt;&gt; hn=sinc(n*wc/pi)*wc/pi;

>> n=-50:50; wc=0.4pi; >> hn=sinc(nwc/pi)*wc/pi;