1 / 27

Soil Water Content - PowerPoint PPT Presentation

Soil Water Content. Soil Moisture Content. Water that may be evaporated from soil by heating at 105 0 C to a constant weight. mass of water evaporated (g). Gravimetric moisture content (w) =. mass of dry soil (g). volume of water evaporated (cm 3 ). Volumetric moisture content ( q ) =.

Related searches for Soil Water Content

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

PowerPoint Slideshow about 'Soil Water Content' - percy

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

Soil Moisture Content

Water that may be evaporated from soil by heating at 1050C to a constant weight

mass of water evaporated (g)

Gravimetric moisture content (w) =

mass of dry soil (g)

volume of water evaporated (cm3)

Volumetric moisture content (q) =

volume of soil (cm3)

bulk density of soil

q = w *

density of water

mass of dry soil (g)

Bulk density of soil (r) =

volume of soil (cm3)

Example: A soil is sampled by a cylinder measuring 7.6 cm in diameter and 7.6 cm length. Calculate gravimetric and volumetric water contents, and wet and dry bulk densities using the following data:

• Weight of empty cylinder = 300 g

• Weight of cylinder + wet soil = 1000 g

• Weight of cylinder + oven dry (1050C) soil = 860 g

Volume of cylinder = p*r2*h = 3.14*(7.6/2)2*7.6 = 345 cm3

Weight of wet soil = 1000 – 300 = 700 g

Weight of dry soil = 860 – 300 = 560 g

Dry bulk density = 560/345 = 1.62 g cm-3

Gravimetric moisture content = (700-560)/560 = 0.25 or 25%

Volumetric moisture content = r *w = 1.62*0.25 = 0.41 or 41%

Know how to do these calculations for

quiz on Friday

Weigh drying pan, moist soil subsample + pan,

Oven dry the subsample at 105C for 24 hr,

Weigh the dried soil + pan.

Calculate the moisture content (w):

w = (g moist soil – g dry soil)/(g dry soil – pan)

Rearrange the eqn to solve for dry soil wt.

Dry soil wt = g moist soil / (1 + w)

Direct method

(Gravimetric)

Indirect methods

(need to calibrate)

Electrical properties

Acoustic method

Thermal properties

Chemical methods

-Neutron scattering

-g- ray attenuation

Electrical Conductance

Dielectric constant

TDR

- Gypsum blocks

- Nylon blocks

- Change in conductance

Principles underlying different methods of

assessment of soil water content

Direct

Gravimetric: evaporating water at 1050C (be able to do the calc’ns)

Indirect

Neutron scattering:

Thermalization

Time domain reflectrometry:

Dielectric constant

In-direct:

Watermark (granular matrix sensor), gypsum block

Direct: Tensiometer

http://www.bae.ncsu.edu/programs/extension/evans/ag452-3.html

Gently tap a tube into the soil to take an undisturbed sample from the center of the effective root zone.

Trim the soil at each end of the tube to the tube length so that the soil occupies the exact tube volume.

Calibration for moisture content that the soil occupies the exact tube volume.

• Measure and weigh the tube

• Weigh the field moist soil + tube

• Oven dry the soil from the tube

• Calculate:

W = g water/g dry soil = (wet – dry) / dry soil

Db = g dry soil / cm3 volume soil

Θ = (W x Db) / Dw

• Compare lab moisture content to field measurements

• For water potential, compare water retention curves derived in lab using pressure plates.

Water retention curves: that the soil occupies the exact tube volume. Water content vs pressure or tension

Note: clay holds more water at a specific water potential than sand or loam;

Water is held tighter at a given water content in clay than in sand.

Structure is predominant at low potentials; as soil dries out, texture is more important

Effect of structure on water flow that the soil occupies the exact tube volume.

www.soils.umn.edu/.../soil2125/doc/s7chp3.htm

The flow of water in soil that the soil occupies the exact tube volume.

Saturated and unsaturated

flow

Saturated flow that the soil occupies the exact tube volume.

Ksat = Q/A x L/(Ψ1 - Ψ2)

where Q is volume of water in time (t)

A is area of cross section

Ksat is saturated hydraulic conductivity of soil (how fast water moves)

L is length of column

Ψ is the water potential at points 1 and 2

Flux can be thought of as water flowing from a hose. The flux is the rate of water discharged by the hose, divided by the cross-sectional area of the hose.

http://soils.usda.gov/technical/technotes/note6fig1.jpg

Saturated flow in soils flux is the rate of water discharged by the hose, divided by the cross-sectional area of the hose.

• The pores are full of water and matric potential is considered to be negligible

because at least some of the water is a long distance from solid surfaces

• Under these conditions, flow is:Rapid - moving through large poresDriven by gravity and sometimesHydrostatic pressure if water is ponded

http://www.maf.govt.nz/mafnet/schools/activities/swi/swi-04.htmhttp://www.maf.govt.nz/mafnet/schools/activities/swi/swi-04.htm

http://www.montcalm.org/montcalmold/media/planningeduc/tn_gwa5.jpghttp://www.montcalm.org/montcalmold/media/planningeduc/tn_gwa5.jpg

Saturationhttp://www.montcalm.org/montcalmold/media/planningeduc/tn_gwa5.jpg

unsaturated

wet

dry

Unsaturated flowhttp://www.montcalm.org/montcalmold/media/planningeduc/tn_gwa5.jpg

Soil moisture content changing with depth

Unsaturated flow – most common in soilshttp://www.montcalm.org/montcalmold/media/planningeduc/tn_gwa5.jpg

• Occurs along soil surfaces, not through large pores.

• Driven by matric forces that are much stronger than gravity.

Gravity is not sufficiently strong to exert a significant influence on unsaturated flow because much of the soil water adheres to solid surfaces.

• Unsaturated flow is slow.

• Even though the driving force is usually greater than for saturated flow, the resistance to flow is enormous.

• Water will flow toward a lower (more negative) potential regardless of direction (up, down, laterally). In other words it will flow towards:            drier medium            salty solution            finer texture (small pores)

http://www.maf.govt.nz/mafnet/schools/activities/swi/swi-04.htmhttp://www.maf.govt.nz/mafnet/schools/activities/swi/swi-04.htm

http://wwwlb.aub.edu.lb/~webeco/SIM215soilwater_files/image004.gifhttp://wwwlb.aub.edu.lb/~webeco/SIM215soilwater_files/image004.gif