equations of uniform accelerated motion
Download
Skip this Video
Download Presentation
Equations of Uniform Accelerated Motion

Loading in 2 Seconds...

play fullscreen
1 / 15

Equations of Uniform Accelerated Motion - PowerPoint PPT Presentation


  • 260 Views
  • Uploaded on

Equations of Uniform Accelerated Motion . AP Physics C Mrs. Coyle . Uniform Accelerated Motion. Motion with constant acceleration Straight line Same direction. Equations for Uniform Accelerated Motion. Velocity v= v o + at Position x= x o + v o t + ½ at 2

loader
I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
capcha
Download Presentation

PowerPoint Slideshow about 'Equations of Uniform Accelerated Motion' - neka


An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
uniform accelerated motion
Uniform Accelerated Motion
  • Motion with constant acceleration
    • Straight line
    • Same direction
equations for uniform accelerated motion
Equations for Uniform Accelerated Motion
  • Velocity v= vo+ at
  • Position x= xo + vot + ½ at2
  • v2 = vo2 + 2a(x-xo)

Remember:

Displacement= Dx = x-xo

more equations of motion for uniform accelerated motion
MoreEquations of Motion for Uniform Accelerated Motion
  • vavg= ½ (vo+v)
  • Dx = ½ (vo+ v)t
  • Assume that ti=0
example of position vs time positive acceleration
Example of Position vs Time (Positive Acceleration)

Position (m)

x= xo + vot + ½ at2

Parabola

o

Time (s)

Slope of Tangent at a given time= Instantaneous Velocity at that time

slide6
Example of Velocity vs Time (Positive Acceleration)

v= vo+ at

Velocity (m/s)

o

Time (s)

Slope of Line= Acceleration

Area Under Line=Displacement

slide7
Example of Acceleration vs Time (Const. a)

Acceleration (m/s2)

o

Time (s)

Area under line = Change in Velocity

slide8
How do we derive Dx = ½ (vo+ v)t

from the graph?

v

Velocity (m/s)

vo

o

Time (s)

t

Hint: Area Under the Line=Displacement Δx

slide10
Example of Velocity vs Time (Negative Acceleration)

Velocity (m/s)

o

Time (s)

Slope of Line= Acceleration

Area Under Line=Displacement

slide11
Example of Acceleration vs Time (Negative a)

Acceleration (m/s2)

o

Time (s)

Area under line = Change in Velocity

how do we derive x x o v o t at 2
How do we derive x= xo + vot + ½ at2?

Hint: Start with Dx = ½ (vo+ v)t

and then substitute for vthat v= vo+at.

how do we derive v 2 v o 2 2a x x o
How do we derive v2 = vo2 + 2a(x-xo)?
  • Hint: Start with Dx = ½ (vo+ v)t

then substitute for t= (v– vo) /a

problem 1
Problem 1

A ball initially stationary, accelerates at 0.25m/s2 down a 2m inclined plane. It then rolls up another incline, where it comes to rest after rolling up 1m.

a) What is the speed of the ball at the bottom of the incline and how much time did this take?

b) What is the acceleration along the second plane?

Answer: a) 1m/s, 4sec, b) -0.5m/s2

problem 2
Problem 2

A Mustang travelling with a constant velocity of 35m/s, passes a stationary police car.

The reaction time of the officer was 2.5sec and he then accelerates at 5.0 m/s2 to catch the Mustang. How long does it take for the police car to catch the Mustang?

Answer: 15.8sec

ad