1 / 5

Chapter 10

Chapter 10. More with angular rotatoin. Cross product (Vector Product). The solution of a vector product AxB is a vector in a direction that is perpendicular to the two vectors A and B. (Right hand rule) A X B = - B X A [ A X B ] = AB sin (theta) i xj =- jxi = k

morwenna-awena
Download Presentation

Chapter 10

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 10 More with angular rotatoin

  2. Cross product(Vector Product) • The solution of a vector product AxB is a vector in a direction that is perpendicular to the two vectors A and B. (Right hand rule) • A X B = -B X A • [A XB] = AB sin (theta) • ixj =-jxi = k • jxk = -kxj = i • kxi = -ixk = j • ixi = jxj = kxk = 0

  3. A x B = (Axi+ Ayj + Azk) x (Bxi+ Byj+ Bzk) = (Ay Bz - Az By )i = (AzBx - AxBz) j = (AX BY - AYBX) K

  4. Determinate method (Ay Bz - Az By )i + (AzBx - AxBz) j + (AX BY - AYBX) k

  5. Relating rotational with translational • Linear momentum • Torque

More Related