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Force on a string segment D x : (from when we derived the wave equation)

Reflection and Transmission. What force must be applied at end of a string to launch a pulse?. THERE ARE TWO FORCES TO CONSIDER !!!!!!. Force on a string segment D x : (from when we derived the wave equation).

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Force on a string segment D x : (from when we derived the wave equation)

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  1. Reflection and Transmission What force must be applied at end of a string to launch a pulse? THERE ARE TWO FORCES TO CONSIDER !!!!!! Force on a string segment Dx: (from when we derived the wave equation) As Dxgoes to zero, Fy and mass go to zero, but acceleration of the string segment remains finite. It had better – we need a force to move the string to get a wave equation !

  2. T Vertical force at the string end: (Tension force at end) The Impedance Creed The string end is an interface. It has no width. It has no mass. There is no limit to apply. It cannot have a net force applied to it. A net force would be equivalent to an infinite stress. A net force at the end would rip the string. The driver must therefore balance this force.

  3. If y = f(x-vt): Force needed is proportional to the transverse velocity, like a damping force!

  4. Constant of proportionality is the characteristic impedance: The change in impedance at an interface determines the amounts of reflection and transmission. The string must be continuous at the boundary:

  5. The force must balance at the boundary: Integrate with respect to time:

  6. reflection coefficient transmission coefficient

  7. Into more dense medium Into less dense medium

  8. Impedance Matching: No Reflection! (not really an interface)

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