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Boyle’s law lab. Purpose: to investigate mathematical relationship between pressure and volume Sample calculations: Diameter of piston  2.40 cm (2.30-2.50) Radius  1.20 cm Area   r 2  4.52 cm 2 (4.15 - 4.91) Book pressure  average book weight

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Boyle’s law lab


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boyle s law lab
Boyle’s law lab
  • Purpose: to investigate mathematical relationship between pressure and volume
  • Sample calculations:

Diameter of piston  2.40 cm (2.30-2.50)

Radius  1.20 cm

Area r2 4.52 cm2 (4.15 - 4.91)

Book pressure average book weight

area of contact

 850 g / 4.52 cm2

 188 g / cm2 (173 - 205)

PV column should be 36,000 all the way down

slide2

y = mx + b

P = (constant)(1/V) + 0

PV = constant (answer to both 1 and 2)

conclusions and questions
Conclusions and Questions
  • If P doubles, V is cut in half. If P is tripled, V becomes 1/3 of its original value.
  • “As the pressure on a gas increases, the volume of the gas decreases proportionally, provided that the temperature and amount of gas remain constant”. I.e. P1V1 = P2V2.
  • As volume decreases, there are more collisions with the side of the container per unit of time, thus the pressure increases.
  • P1=103kPa, V1=5.2L, P2=400kPa, V2=?

Using Boyle’s law: P1V1 = P2V2,

103 kPa x 5.2 L = 400 kPa x V2

V2= (103 kPa x 5.2 L) / 400 kPa = 1.34 L

slide4
P1= 700 mm Hg x 1 atm / 760 mm Hg = 0.921 atm, V1= 200 ml, P2= ?, V2= 950 ml

Using Boyle’s law: P1V1 = P2V2

0.921 atm x 200 ml = P2 x 950 ml

P2= (0.921 atm x 200 ml)/950ml=0.194 atm

conclusion
Conclusion
  • By comparing values in the PV column and via the graph we see that PV = constant
  • This is called Boyle’s law (after the scientist that first discovered the relationship)
  • We will be looking more closely at Boyle’s law
  • For example, using the form P1V1 = P2V2
  • Read “Results of Boyle’s Law Experiment” on handout. Do questions 1 – 6.

For more lessons, visit www.chalkbored.com