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# Titrations Homework Solutions Page 602

Titrations Homework Solutions Page 602. Class Example:. NaOH (aq) + CH 3 COOH (aq)  NaCH 3 COO (aq) + H 2 O (l) 0.500 mol/L 15.00mL 7.5 mL C = ? n NaOH = Cv = (0.500 mol/L)(0.0075L) = 0.00375 mol n CH 3 COOH = (0.00375 mol) (1:1 ratio)

## Titrations Homework Solutions Page 602

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1. TitrationsHomework SolutionsPage 602

2. Class Example: NaOH(aq) + CH3COOH(aq) NaCH3COO(aq) + H2O(l) 0.500 mol/L15.00mL 7.5 mL C = ? nNaOH = Cv = (0.500 mol/L)(0.0075L) = 0.00375 mol nCH3COOH = (0.00375 mol) (1:1 ratio) [CH3COOH] = 0.00375 mol/0.015 L = 0.25 mol/L

3. Practice Problems, Page 602: #17) HNO3(aq) + NaOH(aq) NaNO3(aq)+ H2O(l) 17.85 mL25.00mL 0.150 mol/L nNaOH = Cv = (0.025 mol/L)(0.150 L) = 0.00375 mol nHNO3 = 0.00375 mol 1:1 ratio [HNO3] = 0.00375 mol/0.01785 L = 0.210 mol/L

4. Practice Problems, Page 602: #18) Mg(OH)2(aq) + 2HCl(aq) MgCl2(aq)+ 2H2O(l) 1.015 mol/L40.00mL 1.60 mol/L nHCl = Cv = (1.60 mol/L)(0.04 L) = 0.064 mol nMg(OH)2 = 0.064 mol HCl X 1 Mg(OH)2 = 0.032 mol Mg(OH)2 2 HCl [Mg(OH)2] = 1.015 mol/L VMg(OH)2 = n = 0.032 mol = 0.0315 L = 31.5 mL c 1.015 mol/L

5. Practice Problems, Page 602: 19a) HCl(aq) + NaOH(aq) NaCl(aq)+ H2O(l) 0.150 M25.00mL 0.135 mol/L nNaOH = Cv = (0.135 mol/L)(0.025 L) = 0.003375 mol NaOH nHCl = 0.003375 mol HCl (1:1 ratio) VHCl = n = 0.003375 mol = 0.0225 L = 22.5 mL c 0.150 mol/L

6. Practice Problems, Page 602: b) HCl(aq) + NH3(aq) NH4Cl(aq) 0.150 M20.00mL 0.185 mol/L nNH3 = Cv = (0.185 mol/L)(0.02 L) = 0.0037 mol NaOH nHCl = 0.0037 mol (1:1 ratio) VHCl = n = 0.0037 mol = 0.02467 L = 24.7 mL c 0.150 mol/L

7. Practice Problems, Page 602: c) 2HCl(aq) + Ca(OH)2(aq) 2H2O(l) + CaCl2(aq) 0.150 M80.00mL 0.0045 mol/L nCa(OH)2 = Cv = (0.0045 mol/L)(0.08 L) = 3.6 X 10-4 mol nHCl = 3.6 X 10-4 mol Ca(OH)2 X 2 HCl= 7.2 X 10-4 mol HCl 1 Ca(OH)2 VHCl = n = 7.2 X 10-4 mol = 0.0048 L = 4.80 mL c 0.150 mol/L

8. Practice Problems, Page 602: 20a) NaOH(aq) + HFaq) H2O(l) + NaF(aq) 37.82mL15.00mL 0.250 mol/L nHF= Cv = (0.250 mol/L)(0.015 L) = 0.00375mol nNaOH= 0.00375 mol (1:1 ratio) [NaOH] = n = 0.00375mol = 0.09915 L  0.0992 mol/L V 0.03782 L

9. Practice Problems, Page 602: b) 2NaOH(aq) + H2SO4(aq) Na2SO4(aq) + 2H2O(l) 21.56 mL20.00mL 0.145 mol/L nH2SO4 = Cv = (0.145 mol/L)(0.02 L) = 0.0029 mol nNaOH= 0.0029 mol H2SO4 X 2 NaOH= 0.0058 mol NaOH 1 H2SO4 [NaOH] = n = 0.0058mol = 0.269 mol/L c 0.02156 L

10. Practice Problems, Page 602: c) 3NaOH(aq) + H3PO4(aq) Na3PO4(aq) + 3H2O(l) 14.27 mL25.00mL 0.105 mol/L nH3PO4 = Cv = (0.105 mol/L)(0.025 L) = 0.00262 mol nNaOH= 0.00262 mol H3PO4 X 3 NaOH= 0.007875 mol NaOH 1 H3PO4 [NaOH] = n = 0.007875mol = 0.550 mol/L c 0.01427 L

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