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CH. 2 - MEASUREMENT PowerPoint Presentation
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CH. 2 - MEASUREMENT

CH. 2 - MEASUREMENT

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CH. 2 - MEASUREMENT

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  1. CH. 2 - MEASUREMENT III. Unit Conversions (p. 40 - 42) C. Johannesson

  2. To the left or right? A. SI Prefix Conversions 1. Find the difference between the exponents of the two prefixes. 2. Move the decimal that many places. C. Johannesson

  3. NUMBER = UNIT A. SI Prefix Conversions 0.532 532 m = _______ km NUMBER UNIT C. Johannesson

  4. mega- kilo- k M 106 103 BASE UNIT deci- d --- 100 10-1 centi- c 10-2 milli- m 10-3 micro-  10-6 nano- n 10-9 pico- p 10-12 A. SI Prefix Conversions Prefix Symbol Factor move left move right C. Johannesson

  5. 1) 20 cm = ______________ m 2) 0.032 L = ______________ mL 3) 45 m = ______________ nm 4) 805 dm = ______________ km A. SI Prefix Conversions 0.2 32 45,000 0.0805 C. Johannesson

  6. B. Dimensional Analysis • The “Factor-Label” Method • Units, or “labels” are canceled, or “factored” out C. Johannesson

  7. B. Dimensional Analysis • Steps: 1. Identify starting & ending units. 2. Line up conversion factors so units cancel. 3. Multiply all top numbers & divide by each bottom number. 4. Check units & answer. C. Johannesson

  8. B. Dimensional Analysis • Lining up conversion factors: = 1 1 in = 2.54 cm 2.54 cm 2.54 cm 1 = 1 in = 2.54 cm 1 in 1 in C. Johannesson

  9. qt mL  B. Dimensional Analysis • How many milliliters are in 1.00 quart of milk? 1 L 1.057 qt 1000 mL 1 L 1.00 qt = 946 mL C. Johannesson

  10. lb cm3 B. Dimensional Analysis • You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3. 1 cm3 19.3 g 1 kg 2.2 lb 1000 g 1 kg 1.5 lb = 35 cm3 C. Johannesson

  11. in3 L B. Dimensional Analysis • How many liters of water would fill a container that measures 75.0 in3? 1 L 1000 cm3 (2.54 cm)3 (1 in)3 75.0 in3 = 1.23 L C. Johannesson

  12. cm in B. Dimensional Analysis 5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off? 8.0 cm 1 in 2.54 cm = 3.2 in C. Johannesson

  13. cm yd B. Dimensional Analysis 6) Taft football needs 550 cm for a 1st down. How many yards is this? 1 ft 12 in 1 yd 3 ft 1 in 2.54 cm 550 cm = 6.0 yd C. Johannesson

  14. cm pieces B. Dimensional Analysis 7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire? 1 piece 1.5 cm 100 cm 1 m 1.3 m = 86 pieces C. Johannesson