5.4 Midsegment Theorem. Geometry Mrs. Spitz Fall 2004. Objectives:. Identify the midsegments of a triangle. Use properties of midsegments of a triangle. Assignment. Pgs. 290-291 #1-18, 21-22, 26-29. Using Midsegments of a Triangle.
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Use the midpoint formula.Ex. 1: Using midsegments
M = (2, 1)
N = 4+6 , 5+(-1)
N = (5, 2)
Next find the slopes of JK and MN.
Slope of JK = 5 – 3 = 2 = 1
4-(-2) 6 3
Slope of MN= 2 – 1 = 1
5 – 2 3
►Because their slopes are equal, JK and MN are parallel. You can use the Distance Formula to show that MN = √10 and JK = √40 = 2√10. So MN is half as long as JK.Solution:
DE ║ AB, and
DE = ½ ABTheorem 5.9: Midsegment Theorem
UW = ½(RS) = ½ (12) = 6
RT = 2(VW) = 2(8) = 16
A coordinate proof of Theorem 5.9 for one midsegment of a triangle is given on the next slide. Exercises 23-25 ask for proofs about the other two midsegments. To set up a coordinate proof, remember to place the figure in a convenient location.Ex. 2: Using the Midsegment Theorem
Place points A, B, and C in convenient locations in a coordinate plane, as shown. Use the Midpoint formula to find the coordinate of midpoints D and E.Ex. 3: Proving Theorem 5.9
D = 2a + 0 , 2b + 0 = a, b
E = 2a + 2c , 2b + 0 = a+c, b
Find the slope of midsegment DE. Points D and E have the same y-coordinates, so the slope of DE is 0.
►AB also has a slope of 0, so the slopes are equal and DE and AB are parallel.
Calculate the lengths of DE and AB. The segments are both horizontal, so their lengths are given by the absolute values of the differences of their x-coordinates.
AB = |2c – 0| = 2c DE = |a + c – a | = c
►The length of DE is half the length of AB.
PLOT the midpoints on the coordinate plane.
CONNECT these midpoints to form the midsegments LN, MN, and ML.
FIND the slopes of the midsegments. Use the slope formula as shown.
ML = 3-2 = -1
MN = 4-3 = 1
LN = 4-2 = 2 = 2
Each midsegment contains two of the unknown triangle’s midpoints and is parallel to the side that contains the third midpoint. So you know a point on each side of the triangle and the slope of each side.
►DRAW the lines that contain the three sides.
The lines intersect at 3 different points.
A (3, 5)
B (7, 3)
C (1, 1)
The perimeter formed by the three midsegments of a triangle is half the perimeter of the original triangle shown in example #5.
EF = ½ AC = ½ (10) = 5
ED = ½ BC=½ (14.2)= 7.1
►The perimeter of ∆DEF is 5 + 5 + 7.1, or 17.1. The perimeter of ∆ABC is 10 + 10 + 14.2, or 34.2, so the perimeter of the triangle formed by the midsegments is half the perimeter of the original triangle.Ex. 5: Perimeter of Midsegment Triangle