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Design of Retention Pond & Culvert for Middle Fork Wild Cat Creek Watershed

Final project by Ibrahim M.M. Aly focusing on pond and culvert design, water pollution study using computer models. Methods include HEC-1 and L-THIA NPS pollution modeling. Rainfall data and runoff calculations were used to determine volumes and discharge rates. The design features a spillway configuration with specified elevations and coefficients to manage peak flow and detention time. The project also includes culvert design using L-THIA NPS for annual runoff estimation. Contaminant amounts for various substances were analyzed in the watershed.

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Design of Retention Pond & Culvert for Middle Fork Wild Cat Creek Watershed

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  1. ABE 527 Computer Models in Environmental and Natural Resources Engineering Final Project Presented by Ibrahim M M Aly

  2. Project Objectives:- Design of a retention pond for the Middle fork Wild cat Creek watershed, design of culvert and study of the water polution in that watershed. Methods :- * Using HEC_1 * Design of Culvert * L-THIA NPS pollution

  3. Middle Fork Wild Cat Creek watershed

  4. Middle Fork Wild Cat Creek watershed Streams

  5. CN(av) = 340910.80/4347.181 = 78.42 S = 1000/CN – 10 = 2.75 inch

  6. http://danpatch.ecn.purdue.edu/~sprawl/Tools/Runoff/rain.htm Rainfall Depth The rainfall depth for Carroll County, Indiana, with a return period of 25 years and a duration of 2 hour is 2.84 inches. Data is from Rainfall Frequency Atlas of the Midwest, F.A. Huff and J.R. Angel, Midwestern Climate Center and the Illinois State Water Survey, Champaign, IL, 1992. Rainfall Depth The rainfall depth for Clinton County, Indiana, with a return period of 25 years and a duration of 2 hour is 2.99 inches. Data is from Rainfall Frequency Atlas of the Midwest, F.A. Huff and J.R. Angel, Midwestern Climate Center and the Illinois State Water Survey, Champaign, IL, 1992.  The average Rainfall Depth (P) = (2.84+2.99)/2 = 2.915 inch The Runoff Depth (Q) = (P-.2*S)^2/(P+.8*S) = (2.915-.2*2.75)^2/(2.915+.8*2.75) = 1.0935 inch = 2.78 cm

  7. Total Runoff Volume = 1.0935*2.54/100*4347*10000 = 1,207,400 cubic meters If we consider this volume will accumulate in 2 hours, Discharge Volume = 168 cubic meter/ second

  8. Assume a pond of 15 acre area Area elevation  15 670 15 692 For the outlet we use Centerline elevation of 670 ft. Discharge coefficient = 0.6 Exponent = .5 Spillway configuration Crest Elevation = 690 ft Exponent = 1.5, Length = 20 ft, discharge coefficient = 4.03. I also used 6 pipes of 24”each for the outlet The pond peak flow is 811 cfs and the detention time is 11.20 hr That is reduced from 2400 cfs

  9. The Culvert Design

  10. Using L-THIA NPS for avg. annual estimation CN(avg.) = 78.2946 (78.42 previous calculation) Avg. annual runoff volume = 1,428,038 cubic meters Avg. annual runoff depth = 3.29 cm

  11. Contaminant Amount (kg) Total Nitrogen 6012 Total_Kjeldahl_Nitrogen 2331 Nitrate_Nitrite_(kgasN) 2190 Total_Phosphorus 1763 Dissolved_Phosphorus 4.786 Suspended_Solids 145421 Dissolved_Solids 1671971 Total Lead 2.560 Total_Copper 2.939 Total Zinc 24.717 Total_Cadmium 1.414 Total_Chromium 14.10 Total_Nickel 0.2139 BOD 5890 COD 1750

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