1 / 10

Practice Energy Calculation Quiz

Practice Energy Calculation Quiz.

kolton
Download Presentation

Practice Energy Calculation Quiz

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Practice Energy Calculation Quiz

  2. How much energy does it take to convert 722 grams of ice at 211C to steam at 675C?(Be sure to draw and label the appropriate heating or cooling curve.)Provided information:heat of fusion = 6.0 kJ/molheat of vaporization = 40.7 kJ/molspecific heat capacity of ice = 2.1 J/g∙Cspecific heat capacity of steam = 1.8 J/g∙C

  3. Label the graphs with the correct temperatures!

  4. Step 1: Convert the mass in grams to moles. 722 mole H2O 1 g H2O = 40.1 molH2O 18.0 g H2O

  5. Step 2Heat the ice from 211C to its melting point of 0C. q = mcΔT q = (722 g)(2.1 J/g∙C)(0  (211C)) q = 3.20 x 105 J

  6. Step 3Convert ice to liquid water - (melt the ice!!) q = ΔHfusion ∙moles q = (6.0 kJ/mol)(40.1 mol) q = 241 kJ = 241,000 J

  7. Step 4Heat the ice from 0C to its boiling point of 100C. q = mcΔT q = (722 g)(4.18 J/g∙C)(100  0C) q = 302,000 J

  8. Step 5Convert water to steam - (boil the water!!) q = ΔHvaporization ∙moles q = (40.7 kJ/mol)(40.1 mol) q = 1630 kJ = 1,630,000 J

  9. Step 6Heat the steam from 100C to 675C. q = mcΔT q = (722 g)(1.8 J/g∙C)(675  100C) q = 747,000J

  10. qtotal = q2+ q3 +q4 +q5+ q6 Step 7: Add the heats! qtotal= 3.2 x 105 J + 241, 000 J + 302,000 J + 1, 630,000 J + 747,000 J qtotal= 3,240,000 J or 3.24 x 106 J qtotal = 3,240 kJ or 3.24 x 103 kJ

More Related