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**The gradient or gradient of a line is a number that tells us**how “steep” the line is and which direction it goes. This one has the greatest gradient If you move along the line from left to right and are climbing, it is a positive gradient. This one has the smallest gradient gradient These are all positive gradients. The “steeper” the line, the larger the gradient value.**We compute the gradient by taking the ratio of how much the**line rises (goes up) and how much the line runs (goes over) We could compute the run by looking at the difference between the x values. run (x2, y2) y2 - y1 If we took two points on the line, we could compute the rise by looking at the difference between the y values. rise (x1, y1) x2 - x1 So the gradient or gradient is the rise over the run This is the gradient formula gradient is designated with an m**This one has the greatest absolute value gradient**If you move along the line from left to right and are descending, it is a negative gradient. This one has the smallest absolute value gradient These are all negative gradients. The “steeper” the line, the larger the absolute value of the gradient. (basically this means if you ignore the negative, the larger the number, the steeper the line---but in the negative gradient direction). Gradient**Let’s figure out the gradient of this line. We know it**should be a positive number. (2, 4) Choose two points on the line. 1 (1, 2) The rise over the run is 2 over 1 which is 2. Let’s compute it with the gradient formula. 2 (0, 0) (-2, -4) What if we'd chosen two different points on the line? It doesn't matter which two points we pick, we'll always get a constant ratio of 2 for this line.**If we look at any points on this line we see that they all**have a y coordinate of 3 and the x coordinate varies. Let's choose the points (-4, 3) and (2, 3) and compute the gradient. (-4, 3) (2, 3) (-1, 3) This makes sense because as you go from left to right on the line, you are not rising or falling (so zero gradient). The equation of this line is y = 3 since y is 3 everywhere along the line. In general, the equation of a horizontal line is y = b, where b is the y coordinate of any point on the line. In general, the equation of a horizontal line is y = b, where b is the y coordinate of any point on the line.**If we look at any points on this line we see that they all**have a x coordinate of - 2 and the y coordinate varies. Let's choose the points (-2, 3) and (-2, - 2) and compute the gradient. (-2, 3) (-2, 0) (-2, -2) Dividing by 0 is undefined so we say the gradient is undefined. You can't go from left to right on the line since there isn't a left and right. The equation of this line is x = - 2 since x is - 2 everywhere along the line. In general, the equation of a vertical line is x = a, where a is the x coordinate of any point on the line. In general, the equation of a vertical line is x = a, where a is the x coordinate of any point on the line.**positive gradient**It is easy to remember undefined gradient because you can’t move along from left to right (it is vertical) negative gradient undefined gradient zero gradient (or no gradient) It is easy to remember 0 gradient because the line does not slope at all (it is horizontal)**We often have points on a line but want to find an equation**of the line. We'll see how to do this by looking at an example. Find the equation of a line the contains the points (- 2, 4) and (2, - 2). First let's plot the points and graph the line. Now let's compute the gradient---we know it will be negative by looking at the line. (x, y) Pick a general point on the line, (x, y). (2, -2) Use the point (2, -2) and this general point in the gradient formula subbing in the gradient we found. This is an equation for the line. Let's get it in a neater form. If we get rid of brackets and fractions and get the x and y on one side (with positive x term) and constants on the other side we'll have standard form.**If we get rid of brackets and fractions and get the x and y**on one side (with positive x term) and constants on the other side we'll have standard form. get rid of brackets get rid of fractions by multiplying by - 2 get the x and y terms on one side (with positive x term) general or standard form constants on the other side Choose any x and sub it in this equation and solve for y and you will get a point (x, y) that lies on the line. x = 0 (0, 1) is on the line**Let's generalize what we did to get a formula for finding**the equation of a line. Let's call the specific point we know on the line (x1, y2). (x - x1) Multiply both sides by x - x1 (x - x1) rearranging a bit we have: This is called the point-gradient formula because it will find the equation of a line when you have a specific point (x1, y2)on the line and the gradient. We can also use it when we know two points on the line because we could find the gradient first and then use one of the points for the specific point.**Remember that gradient is the change in y over the change in**x. The gradient is 2 which can be made into the fraction -1 -1 0 0 Example when you have a point and the gradient A point on a line and the gradient of the line are given. Find two additional points on the line. +1 +2 To find another point on the line, repeat this process with your new point (0,3) (0,3) +1 +2 So this point is on the line also. You can see that this point is found by changing (adding) 2 to the y value of the given point and changing (adding) 1 to the x value. (1,1) (1,5)**-1**-1 0 0 A way to do the last problem using the equation of the line A point on a line and the gradient of the line are given. Find two additional points on the line. x = 0 If we find the equation of the line using the point-gradient formula, we can easily find additional points on the line by subbing in various x values and finding the y values. (1,5)**-1**-1 0 0 Let's take this equation and solve for y. This form of the equation is called gradient-intercept form because it contains the gradient and the y intercept of the line. gradient-intercept form**y intercept**gradient Example of given an equation, find the gradient and y intercept Find the gradient and y intercept of the given equation and graph it. First let's get this in gradient-intercept form by solving for y. -3x +4 -3x +4 Now plot the y intercept -4 -4 Change in y Change in x From the y intercept, count the gradient Now that you have 2 points you can draw the line**Acknowledgement**I wish to thank Shawna Haider from Salt Lake Community College, Utah USA for her hard work in creating this PowerPoint. www.slcc.edu Shawna has kindly given permission for this resource to be downloaded from www.mathxtc.com and for it to be modified to suit the Western Australian Mathematics Curriculum. Stephen Corcoran Head of Mathematics St Stephen’s School – Carramar www.ststephens.wa.edu.au