1 / 17

# ?? (beat) ???? ??????????????? - PowerPoint PPT Presentation

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about '?? (beat) ???? ???????????????' - kalia-rogers

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

y1=0

x2=-100

y2=0

lambda=25

w1=1

w2=0.9

k1

k2

v

dx=300.0/(n-1);

for(int i=0;i<n;i++)

{

for(int j=0;j<n;j++)

{

x[i][j]=-150+dx*i;

y[i][j]=-150+dx*j;

}

}

{

for(int j=0;j<n;j++)

{

dx=x[i][j]-x1;

dy=y[i][j]-y1;

r=Math.sqrt(dx*dx+dy*dy);

z[i][j]=Math.cos(k1*r-w1*t);

dx=x[i][j]-x2;

dy=y[i][j]-y2;

r=Math.sqrt(dx*dx+dy*dy);

z[i][j]=z[i][j]+Math.cos(k2*r-w2*t);

}

}

t=t+dt;

nl 200

xl [nl]

yl [nl]

xsize [nl]

ysize [nl]

yl2

dx=360.0/(n-1);

for(int i=0;i<n;i++)

{

x[i]=-180.0+dx*i;

y[i]=-10;

x0[i]=-180.0+dx*i;

}

K=2*3.14159/lambda;

for(int i=0;i<n;i++)

{

s=A*Math.cos(k*x0[i]-w*t);

x[i]=x0[i]+s;

}

t=t+dt;

X長度:位置向量在x方向的投影

y長度:位置向量在y方向的投影

x=x+vx*dt;y=y+vy*dt;t=t+dt;

if (x>=150) vx=-vx;if (x<=-150) vx=-vx;if (y>=150) vy=-vy;if (y<=-150) vy=-vy;

for(int i=0;i<n;i++){ x[i]=-150+Math.random()*300; y[i]=-150+Math.random()*300; vx[i]=-30+Math.random()*60; vy[i]=-30+Math.random()*60; }

for(int i=0;i<n;i++){x[i]=x[i]+vx[i]*dt;y[i]=y[i]+vy[i]*dt;}t=t+dt;

for(int i=0;i<n;i++){if (x[i]>=150) vx[i]=-vx[i];if (x[i]<=-150) vx[i]=-vx[i];if (y[i]>=150) vy[i]=-vy[i];if (y[i]<=-150) vy[i]=-vy[i];}