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Advance Design of RC Structure. University of Palestine. Lecture 3. Shear Wall Design. Dr. Ali Tayeh. Why shear wall? In this course we will study the shear wall as it is the foremost component employed in Gaza to resist seismic lateral load. Distribution of Lateral Force in Plan

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Advance Design of RC Structure


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slide1

Advance Design of RC Structure

University of Palestine

Lecture 3

Shear Wall Design

Dr. Ali Tayeh

slide2

Why shear wall?

    • In this course we will study the shear wall as it is the foremost component employed in Gaza to resist seismic lateral load.
  • Distribution of Lateral Force in Plan
    • The seismic load (as shear force or as moment) to be distributed in plan according to the relative rigidity (moment of inertia I) of each individual element that will resist the lateral load.
    • The case of shear wall
      • Symmetrical, in plan, shear wall
      • Un-symmetrical shear walls
        • Un-symmetrical in one direction
        • Un-symmetrical in two direction
slide3

Symmetrical Shear Walls

    • When the center of mass is at the same location of the center of rigidity.
    • In plane forces in the walls due to direct shear are computed from:
    • Fi = force acting at the shear wall i
    • Vfn = the shear force acting at the floor level n
    • Ii = Moment of inertia of the shear wall I
    • I = the summation of moment of inertia of all shear walls
slide4

In plane forces in the walls due to direct shear are computed from:

  • Mi = Moment acting at the shear wall i
  • Mfn = the Moment acting at the floor level n
slide5

Example

    • If the total seismic shear at the bas is 200 ton. Calculate the force acting on each wall. The thickness of all shear walls = 30 cm.
slide6

Un-symmetrical shear walls in one direction

    • When there is an eccentricity between the center of mass and the center of rigidity
    • That causes a Torsional eccentricity.
    • Torsional Moment MT.
    • Center of mass
    • Center of rigidity.

L

C.R

C.M

e

V

slide7

y

Lx

C.R

ey

Vx

Ly

C.M

ex

x

Vy

    • The force in each shear wall
  • Un-symmetrical shear walls in

Two direction

    • Torsional eccentricity.

= Accidental eccentricity

slide8

Torsional Moment MT.

  • Center of mass
  • Center of rigidity
slide10

Example

    • If the total seismic shear at the bas is 200 ton. Calculate the force acting on each wall. The thickness of all shear walls = 30 cm

Neglected

Center of mass

slide11

Center of rigidity

The Eccentricity