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Normalized Polish Expression

Normalized Polish Expression. Draw slicing floorplan based on: Initial PE: P 1 = 25V1H374VH6V8VH Dimensions: (2,4), (1,3), (3,3), (3,5), (3,2), (5,3), (1,2), (2,4). M1 Move. Swap module 3 and 7 in P 1 = 25V1H 37 4VH6V8VH We get: P 2 = 25V1H 73 4VH6V8VH

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Normalized Polish Expression

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  1. Normalized Polish Expression • Draw slicing floorplan based on: • Initial PE: P1 = 25V1H374VH6V8VH • Dimensions: (2,4), (1,3), (3,3), (3,5), (3,2), (5,3), (1,2), (2,4) Practical Problems in VLSI Physical Design

  2. M1 Move • Swap module 3 and 7 in P1 = 25V1H374VH6V8VH • We get: P2 = 25V1H734VH6V8VH • Area changed from 11 × 15 to 13 × 14 Practical Problems in VLSI Physical Design

  3. Change on Floorplan Practical Problems in VLSI Physical Design

  4. M2 Move • Complement last chain in P2 = 25V1H734VH6V8VH • We get: P3 = 25V1H734VH6V8HV • Area changed from 13 × 14 to 15 × 11 Practical Problems in VLSI Physical Design

  5. Change on Floorplan Practical Problems in VLSI Physical Design

  6. M3 Move • Swaps 6 and V in P3 = 25V1H734VH6V8HV • We get: P4 = 25V1H734VHV68HV • Area changed from 15 × 11 to 15 × 7 Practical Problems in VLSI Physical Design

  7. Change on Floorplan Practical Problems in VLSI Physical Design

  8. Initial Temperature Calculation • What is average change on cost function? • Initial temperature with acceptance probability 0.9? Practical Problems in VLSI Physical Design

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