1 / 27

BELL-WORK

BELL-WORK. Gateway Bell-Work # 33,34 TB pg 490 #28,34. Reminders. Exam 3.1 will be on Monday! 3 rd Nine Weeks project is due Monday!. HW 3.3. HW 3.3 with corrections are due Tuesday! Practice problems from today’s lesson:

Download Presentation

BELL-WORK

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. BELL-WORK Gateway Bell-Work # 33,34 TB pg 490 #28,34

  2. Reminders Exam 3.1 will be on Monday! 3rd Nine Weeks project is due Monday!

  3. HW 3.3 HW 3.3 with corrections are due Tuesday! Practice problems from today’s lesson: 1. Colette is putting a mat of width 3w and a frame of width w around a 16-inch by 48-inch poster. Find an expression for the amount of frame material she needs. 2. Each side of an equilateral triangle has length 2m + 3. Each side of a square has length 3m – 2. Write an expression for the sum of the perimeter of the equilateral triangle and the perimeter of the square. PW 8-3 # 25-28,39,41

  4. HW 3.3(d) Solutions 1. x2 + 11x + 24 2. y2 + 3y – 28 8. 15t2 – 13t + 2 26. 3w2 + 21w + 36 27. 54c2 – 66c + 16 31. x3 + x2 – 2x + 12 6x3–2x2 – 26x + 24

  5. Guiding question: How are polynomials multiplied?

  6. Real-World Polynomials Each side of an equilateral triangle has length w + 2. Each side of a square has length 3w – 4. Write an expression for the sum of the perimeter of the equilateral triangle and the perimeter of the square.

  7. Real-World Polynomials Each side of an equilateral triangle has length w + 2. Each side of a square has length 3w – 4. Write an expression for the sum of the perimeter of the equilateral triangle and the perimeter of the square.

  8. Real-World Polynomials Each side of an equilateral triangle has length w + 2. Each side of a square has length 3w – 4. Write an expression for the sum of the perimeter of the equilateral triangle and the perimeter of the square. Perimeter of triangle = w + 2 + w + 2 + w + 2

  9. Real-World Polynomials Each side of an equilateral triangle has length w + 2. Each side of a square has length 3w – 4. Write an expression for the sum of the perimeter of the equilateral triangle and the perimeter of the square.

  10. Real-World Polynomials Each side of an equilateral triangle has length w + 2. Each side of a square has length 3w – 4. Write an expression for the sum of the perimeter of the equilateral triangle and the perimeter of the square. Perimeter of square = 3w – 4 + 3w – 4 + 3w – 4 + 3w – 4

  11. Real-World Polynomials Each side of an equilateral triangle has length w + 2. Each side of a square has length 3w – 4. Write an expression for the sum of the perimeter of the equilateral triangle and the perimeter of the square. Sum of perimeters = Perimeter of Tri. + Square = 15w – 10

  12. Real-World Polynomials The volume of a rectangular prism is given by the expression x3 + 2x2 – 4x + 6. The volume of a smaller rectangular prism is given by the expression 4x3 – 5x2 + 6x – 12. How much greater is the volume of the larger prism? x3 + 2x2 – 4x + 6 – (4x3 – 5x2 + 6x – 12) = -3x3 + 7x2 – 10x + 18

  13. Real-World Polynomials Suppose the cost in dollars of producing x model kits is given by the polynomial 500,000 + 2x and the revenue generated from sales is given by the polynomial 30x – 0.00005x2. Find a polynomial expression for the profit from making and selling x model kits, and evaluate the expression for x = 300,000. Profit = Revenue – Cost = 30x – 0.00005x2 – (500,000 + 2x) = -0.00005x2 + 28x – 500,000 When x = 300,000 Profit = 3,400,000

  14. Real-World Polynomials TB pg 489 # 4 Answer = x2 + 2x – 15 TB pg 490 #35 Answer = x2 + 200x + 9375

  15. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  16. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  17. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  18. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  19. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  20. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  21. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame. 2m + 2f + 10

  22. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  23. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame.

  24. Real-World Polynomials Libby is putting a mat of width m and a frame of width f around an 8-inch by 10-inch picture. Write an expression for the perimeter of the frame. 8f + 8m + 36

  25. Find the Area of the Shaded Region

  26. Find the Area of the Shaded Region Area of shaded = Area of whole – Area of un-shaded Area of big rectangle = (3x + 2)(2x – 1) = 6x2 + x – 2 Area of little rectangle = x(x + 3) = x2 + 3x Area of shaded = 6x2 + x – 2 – (x2 + 3x) = 5x2 – 2x – 2

  27. Who wants to answer the Guiding question? How are polynomials multiplied?

More Related