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Harmonik Fonksiyonların Toplamı Periyodik Fonksiyon:

: Örnekleme frekansı. 4. Periyodik sinyaller, fft. Harmonik Fonksiyonların Toplamı Periyodik Fonksiyon:. Örnek 4.1:. clc;clear; w1=3;t1=2*pi/w1;dt=t1/20/3; t=0:dt:t1-dt; x1=2*cos(3*t-1.7); x 2 = -4 *cos( 6 *t +2.1 ); x 3 = 3.2 *cos( 9 *t- 0.65 ); subplot(2,2,1);plot(t,x1)

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Harmonik Fonksiyonların Toplamı Periyodik Fonksiyon:

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  1. : Örnekleme frekansı 4. Periyodik sinyaller, fft Harmonik Fonksiyonların Toplamı Periyodik Fonksiyon: Örnek 4.1:

  2. clc;clear; w1=3;t1=2*pi/w1;dt=t1/20/3; t=0:dt:t1-dt; x1=2*cos(3*t-1.7); x2=-4*cos(6*t+2.1); x3=3.2*cos(9*t-0.65); subplot(2,2,1);plot(t,x1) subplot(2,2,2);plot(t,x2) subplot(2,2,3);plot(t,x3) x=x1+x2+x3; subplot(2,2,4);plot(t,x) pause;close(figure(1)) y=[x,x,x];plot (y)

  3. MatLab’da x: Periyodik sinyalin örnekleri (Örnekleme frekansı: fs=1/dt) fx=fft(x);ampl=2*abs(fx)/length(x);fi=angle(fx); w1=3;t1=2*pi/w1;dt=t1/20/3;t=0:dt:t1-dt; x1=2*cos(3*t-1.7);x2=-4*cos(6*t+2.1);x3=3.2*cos(9*t-0.65); fx=fft(x);ampl=2*abs(fx)/length(x);fi=angle(fx);

  4. Örnek 4.2: x(t) periyodik (T=6.4 s). İlk 4 harmoniğini dikkate alınız. MatLAB’da x: x(t) nin 128 örneği (Δt=0.05). fx=fft(x) , abs(fx): 230.4, 102.4, 51.2, 76.8, 58.88, 3.2, …… angle(fx): 0, -1.86, 2.1, -2.4, 1.6, 0.89, …. x(t)=?, y(t)=? Sistemin öz değerleri: -3±4.6i → Δt=0.0574 s Δt=0.0574 s, fs=17.42 Hz Girdiden Δt= 6.4/20/4 = 0.08 Yanıt: s=2.9451i; h=60*(s+1)/(s^2+6*s+30);a3=abs(h),fi3=angle(h)

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