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  1. Forestry #1 * Forestry #2 * Forestry #3 * Forestry #4 * Forestry #5 * Forestry #6 * Forestry #7 * Forestry #8 * Forestry #9 * Forestry #10 * Forestry #11 * More #1 * More #2 * More #3 * More #4 * More #5 * Forestry Problem Index(click on appropriate number below) Go To Right-of-Way or Aquatic Problems Index *

  2. More #6 * More #7 * More #8 * More #9 * More #10 * And more #19 * And more #20 * And more #21 * And more #22 * And more #23 * Extra #a * Extra #b * Forestry Problem Index (continued)Click on the appropriate number

  3. Right of way #1 * Right of way #2 * Right of way #3 * Right of way #4 * Right of way #5 * Right of way #6 * Right of way #7 * Right of way #8 * Right of way #a * Aquatics #1 * Aquatics #2 * Aquatics #3 * Aquatics #4 * Aquatics #5 * Aquatics #6 * Aquatics #7 * ROW & Aquatic Problem Index(Click on desired problem) Go To Forestry Problem Index *

  4. Forestry problem #1 To prepare 3 gallons of a 3 percent Accord solution requires how manyounces of Accord?

  5. FORESTRY PROB #1 How much Accord is needed? 3 gallons 3% solution FORESTRY PROB #1 1/2

  6. GO TO FORESTRY PROBLEM INDEX 3 gallons x 0.03 = .09 gallon However it is easier to measure this as liquid ounces-- so… 0.09 gal x 128 liq oz / gal = 12 liq oz FORESTRY PROB #1 2/2

  7. Forestry Problem #2 A spray unit with a 400 gallon tank is calibrated to apply 20 gallons per acre. Instructions call for 3 pounds of active ingredient per acre of a 70 percent wettable powder. How many pounds of the product should be added to the tank?

  8. FORESTRY PROB #2 400 gallon tank 20 gal/ac rate 3 lb ai/ac 70% ai product FORESTRY PROB #2 1/4

  9. FORESTRY PROB #2 2/4 Treated acres per tank 400 gal / tank / 20 gal / ac = 20 ac / tank

  10. FORESTRY PROB #2 3/4 Treated acres per tank 20 ac / tank Pounds active ingredient needed 20 ac x 3 lb ai / ac = 60 lb ai

  11. FORESTRY PROB #2 4/4 Treated acres per tank 20 ac / tank Pounds active ingredient needed 60 lb ai Pounds of product needed 60 lb ai / 0 .7 lb ai / lb WP = 86 lb WP GO TO FORESTRY PROBLEM INDEX

  12. Forestry Problem #3 A contractor arrives, and you request a calibration check. The contract requires an application rate of 16 gpa. The check run is made at the planned speed, expending 7 1/2 gallons. You measure the area sprayed, and it is 30 feet by 690 feet. Do you accept the application rate? (In most instances, 5 percent above or below the allowed rate is acceptable.)

  13. FORESTRY PROB #3 Calibration check Require 16 gpa 5% tolerance Sprayed 30’ x 690’ Expended 7.5 gals FORESTRY PROB #3 1/4

  14. How much area sprayed? 30 ft x 690 ft / 43,560 sq. ft / ac = 0.475 ac FORESTRY PROB #3 2/4

  15. How much area sprayed? .475 ac How many gpa? 7.5 gal / 0.475 ac = 15.78 gpa FORESTRY PROB #3 3/4

  16. How much area sprayed? 0.475 ac How many gpa? 7.5 gal / 0.475 ac = 15.78 gpa Rate O.K.? 15.78 gpa / 16 gpa = 98.6% of desired Rate is O.K. (only 1.4% off) GO TO FORESTRY PROBLEM INDEX FORESTRY PROB #3 4/4

  17. Forestry Problem #4 You have a site preparation project. The spray unit tank holds 300 gallons and you want to apply 30 gallons of the mixture per acre. The prescription calls for 1.5 gallons of Garlon 4 per acre, 1/2 percent adjuvant, and 4 ounces of drift control agent per 100 gallons of spray mixture. How much of each would you add per tank?

  18. FORESTRY PROB #4 300 gal tank 30 gal mix per ac 1.5 gal Garlon 4 / ac 0.5% adjuvant 4 liq oz drift control / 100 gal mix FORESTRY PROB #4 1/5

  19. Acres per tank? 300 gal / tank / 30 gal / ac = 10 ac / tank FORESTRY PROB #4 2/5

  20. Acres per tank? 10 ac / tank Gallons of Garlon 4? 10 ac x 1.5 gal / ac = 15 gal FORESTRY PROB #4 3/5

  21. Acres per tank? 10 ac / tank Gallons of Garlon 4? 15 gal Adjuvant? 300 gal x 0.005 = 1.5 gal FORESTRY PROB #4 4/5

  22. GO TO FORESTRY PROBLEM INDEX Acres per tank? 10 ac / tank Gallons of Garlon 4? 15 gal Adjuvant? 1.5 gal Drift control agent? 300 gal x 4 liq oz / 100 gal = 12 liq oz FORESTRY PROB #4 5/5

  23. Forestry Problem #5 You have a 30 acre area to be sprayed with 5 quarts of herbicide per acre in a 20 gallon/acre water spray mixture. The mixture is also to include 4 ounces of drift control agent per 100 gallons. How much of each chemical will you need to do the job, including water?

  24. FORESTRY PROB #5 30 acres to be sprayed 20 gal spray mix / ac (gpa) 5 qt prod / ac 4 liq oz drift retardant / 100 gal mix FORESTRY PROB #5 1/5

  25. Total mixture needed 30 ac x 20 gal /ac = 600 gal FORESTRY PROB #5 2/5

  26. Total mixture needed 600 gal 2,4-DP needed 5 qt / ac x 30 ac= 150 qt (37.5 gal) FORESTRY PROB #5 3/5

  27. Total mixture needed 600 gal 2,4-DP needed 37.5 gal Drift retardant needed 4 liq oz / 100 gal x 600 gal = 24 liq oz FORESTRY PROB #5 4/5

  28. GO TO FORESTRY PROBLEM INDEX Final Solution in tank 600 gallons total mixture as 37.5 gal 2,4-DP 24 oz retardant 562.25 gal of water FORESTRY PROB #5 5/5

  29. Forestry Problem #6 You plan to treat a 60 acre site preparation area with 3 quarts of Garlon 4 and 1 quart Accord per acre. How many gallons of each chemical do you need for the job?

  30. FORESTRY PROB #6 60 acres to be treated 3 qt Garlon 4 + 1 qt Accord / ac FORESTRY PROB #6 1/2

  31. GO TO FORESTRY PROBLEM INDEX Gallons Garlon 4? 60 ac x 3 qt / ac = 180 qt / 4 qt / gal = 45 gallons Gallons Accord? 60 ac x 1 qt / ac = 60 qt / 4 qt / gal = 15 gal FORESTRY PROB #6 2/2

  32. Forestry Problem #7 A ground spray unit is calibrated to apply 40 gallons per acre at 4 mph. The spray unit speeds up to 8 mph. What is the new application rate?

  33. FORESTRY PROB #7 40 gal / ac output at 4 mph new speed 8 mph FORESTRY PROB #7 1/2

  34. GO TO FORESTRY PROBLEM INDEX Rule of thumb Double the speed = 1/2 the coverage 40 gal / ac at 4 mph --> 40/2 gal / ac or 20 gal / ac at 8 mph FORESTRY PROB #7 2/2

  35. Forestry Problem #8 Another spray unit is calibrated to apply 25 gallons per acre at 4 mph. The spray pressure is increased from 15 psi to 60 psi. What is the new application rate?

  36. FORESTRY PROB #8 Calibrated to deliver 25 gpa at 15 psi pressure increased to 60 psi FORESTRY PROB #8 1/3

  37. New rate? Rule of thumb Rate increases as a function of the square root of the pressure increase 60 psi / 15 psi = 4 FORESTRY PROB #8 2/3

  38. GO TO FORESTRY PROBLEM INDEX New rate? New pressure is 4 x old pressure 4 x pressure = 2 x the rate 25 gal x 2 = 50 gpa FORESTRY PROB #8 3/3

  39. Forestry Problem #9 You plan to inject a 40 acre stand with Accord. The Accord is to be diluted with two parts water to one part herbicide, and 1 ml of the diluted mixture is to be injected into each cut, with 2 inches between centers of the injector cuts. There are 400 stems per acre to be treated, with an average stem diameter of 7 inches. How many gallons of undiluted Accord is needed for the project?

  40. FORESTRY PROB #9 40 acres to be treated Accord used at 1:2 in water Inject 1 ml dilution / cut Injection on 2” centers 400 stems per acre Average dbh is 7” FORESTRY PROB #9 1/9

  41. == Reorganize data == 40 acres to be treated 400 stems per acre Average dbh is 7” Injection on 2” centers Inject 1 ml dilution / cut Accord used at 1:2 in water FORESTRY PROB #9 2/9

  42. Number of stems to treat 40 ac x 400 stems / ac = 16,000 stems FORESTRY PROB #9 3/9

  43. Number of stems to treat 16,000 stems Number of cuts per stem 7 in x 3.1416 = 21.98 in circumference 22 in/stem / 2 in/cut = 11 cuts per stem FORESTRY PROB #9 4/9

  44. 7in dbh x 3.1416 (-- “pi”) = 21.98 in circumference Graphically this is: 7” FORESTRY PROB #9 5/9

  45. 22 in/stem / 2 in/cut = 11 cuts / stem x x x x x x 2 in x x x x x FORESTRY PROB #9 6/9

  46. Number of stems to treat 16,000 stems Number of cuts per stem 11 cuts per stem Total number of cuts 16,000 stems x 11 cuts / stem = 176,000 cuts FORESTRY PROB #9 7/9

  47. Total number of cuts 176,000 cuts Total ml of dilution needed 176,000 cuts x 1 ml / cut = 176,000 ml FORESTRY PROB #9 8/9

  48. GO TO FORESTRY PROBLEM INDEX Total number of cuts 176,000 cuts Total ml of dilution needed 176,000 ml = 176 L Total Accord needed 176 L / 3.785 L/gal = 46.5 gal 46.5 gal / 3 [2 water :1 Accord] = 1.5 15.5 gals Accord FORESTRY PROB #9 9/9

  49. Forestry Problem #10 You have a pond which averages 20 feet wide, 100 feet long, and 5 feet deep, with a population of bluegills and rainbow trout. A five gallon container of Accord is accidentally spilled into the pond. Would you expect a fish kill? If so, what could be done to reduce or prevent the kill? (1 cubic foot of water = 28.32 liters; 1 pound = 453.6 grams.)

  50. FORESTRY PROB #10 Pond size - average 20’ wide - 5’ deep - 100’ long Spill 5 gal Accord -- Kill bluegill? Kill rainbow trout? FORESTRY PROB #10 1/9