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Percent composition. C-notes on page 64. Example : Find the % composition of all of the elements within a glucose molecule using the molecules molar mass. You will have to know how to do this to complete future objectives. Glucose: molecular formula = C 6 H 12 O 6

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percent composition

Percent composition

C-notes on page 64

slide2

Example: Find the % composition of all of the elements within a glucose molecule using the molecules molar mass. You will have to know how to do this to complete future objectives.

  • Glucose: molecular formula = C6H12O6
    • (will be given information)
  • Find the molar mass of the compound
  • Find the % of each element with in the compound:

element mass x 100 = %composition

molar mass

glucose molecular formula c 6 h 12 o 6
Glucose: molecular formula = C6H12O6

molar mass =

(12.01 g/mol x 6) + (1.01 g/mol x 12) + (16.00 g/mol x 6)

= 72.06 g/mol + 12.12 g/mol + 96.00 g/mol

= 180.18 g/mol

composition of carbon
% composition of carbon
  • 72.06 g/mol = .3999 x 100 = 39.99% carbon

180.18 g/mol

composition of hydrogen
% composition of hydrogen
  • = 12.12 g/mol = .0673 x 100 = 6.73% hydrogen

180.18 g/mol

composition of oxygen
% composition of oxygen

= 96.00 g/mol= 0.5328 x 100 = 53.28% oxygen

180.18 g/mol

check your answer
Check your answer
  • The end result is that all parts of the compound should equal 100% (or very, very close due to rounding issues)
  • 53.28% + 6.73% + 39.99% = 100%
practice problems for pg 64 will be part of notes
Practice problems for pg 64will be part of notes
  • Write the chemical formula
  • Find the molar mass
  • Find % composition of each element in compound
    • Sodium chloride
    • Aluminum hydroxide
    • Ammonium phosphide
  • Summarize notes and complete practice for stamp
bubble gum lab
Bubble gum lab
  • This will be turned in for a grade.
  • You will need 5 pieces of unchewed gum.
  • We will be going to the lab. While in the lab you need to do the pre lab and steps #1 and #2.
  • DO NOT CHEW THE GUM YET!!!!!!!!!