1 / 47

Introduction to Summary Statistics

Introduction to Summary Statistics. Statistics. The collection, evaluation, and interpretation of data. Statistical analysis of measurements can help verify the quality of a design or process. Summary Statistics. Central Tendency “Center” of a distribution Mean, median, mode Variation

floresp
Download Presentation

Introduction to Summary Statistics

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Introduction to Summary Statistics

  2. Statistics • The collection, evaluation, and interpretation of data • Statistical analysis of measurements can help verify the quality of a design or process

  3. Summary Statistics Central Tendency • “Center” of a distribution • Mean, median, mode Variation • Spread of values around the center • Range, standard deviation, interquartile range Distribution • Summary of the frequency of values • Frequency tables, histograms, normal distribution

  4. Mean Central Tendency • The mean is the sum of the values of a set of data divided by the number of values in that data set.

  5. MeanCentral Tendency

  6. MeanCentral Tendency • Data Set 3 7 12 17 21 21 23 27 32 36 44 • Sum of the values = 243 • Number of values = 11 243 = Mean = = 22.09 11

  7. Mode Central Tendency • Measure of central tendency • The most frequently occurring value in a set of data is the mode • Symbol is M Data Set: 27 17 12 7 21 44 23 3 36 32 21

  8. Mode Central Tendency • The most frequently occurring value in a set of data is the mode Data Set: 3 7 12 17 21 21 23 27 32 36 44 Mode = M = 21

  9. Mode Central Tendency • The most frequently occurring value in a set of data is the mode. • Bimodal Data Set: Two numbers of equal frequency stand out • Multimodal Data Set: If more than two numbers of equal frequency stand out

  10. Mode Central Tendency Determine the mode of 48, 63, 62, 49, 58, 2, 63, 5, 60, 59, 55 Mode = 63 Determine the mode of 48, 63, 62, 59, 58, 2, 63, 5, 60, 59, 55 Mode = 63 & 59 Bimodal Determine the mode of 48, 63, 62, 59, 48, 2, 63, 5, 60, 59, 55 Mode = 63, 59, & 48 Multimodal

  11. Median Central Tendency • Measure of central tendency • The median is the value that occurs in the middle of a set of data that has been arranged in numerical order • Symbol is x, pronounced “x-tilde” ~

  12. Median Central Tendency • The median is the value that occurs in the middle of a set of data that has been arranged in numerical order. Data Set: 27 17 12 7 21 44 23 3 36 32 21

  13. Median Central Tendency • A data set that contains an odd number of values always has a Median. Data Set: 3 7 12 17 21 21 23 27 32 36 44

  14. Median Central Tendency • For a data set that contains an even number of values, the two middle values are averaged with the result being the Median. Data Set: 3 7 12 17 21 21 23 27 31 32 36 44

  15. Range Variation • Measure of data variation. • The range is the difference between the largest and smallest values that occur in a set of data. • Symbol is R Data Set: 3 7 12 17 21 21 23 27 32 36 44 Range = R = 44 – 3 = 41

  16. Standard Deviation Variation • Measure of data variation. • The standard deviationis a measure of the spread of data values. • A larger standard deviation indicates a wider spread in data values

  17. Standard Deviation Variation σ = standard deviation xi = individual data value ( x1, x2, x3, …) μ = mean N = size of population

  18. Standard Deviation Variation Procedure: • Calculate the mean, μ. • Subtract the mean from each value and then square each difference. • Sum all squared differences. • Divide the summation by the size of the population (number of data values), N. • Calculate the square root of the result.

  19. Standard Deviation Calculate the standard deviation for the data array 2, 5, 48, 49, 55, 58, 59, 60, 62, 63, 63 1. Calculate the mean. 2. Subtract the mean from each data value and square each difference. (59 - 47.64)2 = 129.05 (60 - 47.64)2 = 152.77 (62 - 47.64)2 = 206.21 (63 - 47.64)2 = 235.93 (63 - 47.64)2 = 235.93 (2 - 47.64)2 = 2083.01 (5 - 47.64)2 = 1818.17 (48 - 47.64)2 = 0.13 (49 - 47.64)2 = 1.85 (55 - 47.64)2 = 54.17 (58 - 47.64)2 = 107.33

  20. Standard Deviation Variation 3. Sum all squared differences. 2083.01 + 1818.17 + 0.13 + 1.85 + 54.17 + 107.33 + 129.05 + 152.77 + 206.21 + 235.93 + 235.93 = 5,024.55 4. Divide the summation by the number of data values. 5. Calculate the square root of the result.

  21. A Note about Standard Deviation • Two distinct calculations • Population Standard Deviation • The measure of the spread of data within a population. • Used when you have a data value for every member of the entire population of interest. • Sample Standard Deviation • An estimate of the spread of data within a larger population. • Used when you do not have a data value for every member of the entire population of interest. • Uses a subset (sample) of the data to generalize the results to the larger population.

  22. A Note about Standard Deviation σ = population standard deviation xi = individual data value ( x1, x2, x3, …) μ = population mean N = size of population

  23. Sample Standard Deviation Variation

  24. Sample MeanCentral Tendency Essentially the same calculation as population mean

  25. Sample Standard Deviation Estimate the standard deviation for a population for which the following data is a sample. 2, 5, 48, 49, 55, 58, 59, 60, 62, 63, 63 1. Calculate the sample mean. 2. Subtract the sample mean from each data value and square the difference. (2 - 47.64)2 = 2083.01 (5 - 47.64)2 = 1818.17 (48 - 47.64)2 = 0.13 (49 - 47.64)2 = 1.85 (55 - 47.64)2 = 54.17 (58 - 47.64)2 = 107.33 (59 - 47.64)2 = 129.05 (60 - 47.64)2 = 152.77 (62 - 47.64)2 = 206.21 (63 - 47.64)2 = 235.93 (63 - 47.64)2 = 235.93

  26. Sample Standard Deviation Variation 3. Sum all squared differences. 2083.01 + 1818.17 + 0.13 + 1.85 + 54.17 + 107.33 + 129.05 + 152.77 + 206.21 + 235.93 + 235.93 = 5,024.55 4. Divide the summation by the number of sample data values minus one. 5. Calculate the square root of the result.

  27. A Note about Standard Deviation σ = population standard deviation xi = individual data value ( x1, x2, x3, …) μ = population mean N = size of population As n → N, s → σ

  28. A Note about Standard Deviation Given the ACT score of every student in your class, use the population standard deviation formula to find the standard deviation of ACT scores in the class. σ = population standard deviation xi = individual data value ( x1, x2, x3, …) μ = population mean N = size of population

  29. A Note about Standard Deviation Given the ACT scores of every student in your class, use the sample standard deviation formulato estimate the standard deviation of the ACT scores of all students at your school. σ = population standard deviation xi = individual data value ( x1, x2, x3, …) μ = population mean N = size of population

  30. Histogram Distribution • A histogram is a common data distribution chart that is used to show the frequency with which specific values, or values within ranges, occur in a set of data. • An engineer might use a histogram to show the variation of a dimension that exists among a group of parts that are intended to be identical.

  31. Histogram Distribution • Large sets of data are often divided into limited number of groups. These groups are called class intervals. -6 to -16 6 to 16 -5 to 5 Class Intervals

  32. Histogram Distribution • The number of data elements in each class interval is shown by the frequency, which occurs along the Y-axis of the graph 7 5 Frequency 3 1 -16 to -6 6 to 16 -5 to 5

  33. Histogram Distribution Example 1, 7, 15, 4, 8, 8, 5, 12, 10 12,15 1, 4, 5, 7, 8, 8, 10, 4 3 Frequency 2 1 6 to 10 1 to 5 11 to 15

  34. Histogram Distribution • The height of each bar in the chart indicates the number of data elements, or frequency of occurrence, within each range 1, 4, 5, 7, 8, 8, 10, 12,15 4 3 Frequency 2 1 6 to 10 1 to 5 11 to 15

  35. Histogram Distribution MINIMUM = 0.745 in. MAXIMUM = 0.760 in. Class Intervals

  36. Dot Plot Distribution 0 3 -1 -3 3 2 1 0 -1 -1 2 1 0 1 -1 -2 1 2 1 0 -2 -4 0 0 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6

  37. Dot Plot Distribution 0 3 -1 -3 3 2 1 0 -1 -1 2 1 0 1 -1 -2 1 2 1 0 -2 -4 0 0 5 Frequency 3 1 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6

  38. Normal Distribution Distribution “Is the data distribution normal?” • Translation: Is the histogram/dot plot bell-shaped? • Does the greatest frequency of the data values occur at about the mean value? • Does the curve decrease on both sides away from the mean? • Is the curve symmetric about the mean?

  39. Normal Distribution Distribution Bell shaped curve Frequency -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Data Elements

  40. Normal Distribution Distribution • Does the greatest frequency of the data values occur at about the mean value? Mean Value Frequency -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Data Elements

  41. Normal Distribution Distribution • Does the curve decrease on both sides away from the mean? Mean Value Frequency -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Data Elements

  42. Normal Distribution Distribution • Is the curve symmetric about the mean? Mean Value Frequency -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Data Elements

  43. What if things are not equal? Histogram Interpretation: Skewed (Non-Normal) Right

  44. Normal Distribution Distribution • 68%of the observations fall within 1 standard deviation of the mean. • 95%of the observations fall within 2 standard deviationsof the mean. • 99.7%of the observations fall within 3 standard deviationsof the mean. If the data are normally distributed:

  45. Normal Distribution Example Data from a sample of a larger population

  46. Normal Distribution Distribution 0.08 + 1.77 = 1.88 0.08 + - 1.77 = -1.69 68 % s +1.77 s -1.77 Data Elements

  47. Normal Distribution Distribution 0.08 + -3.54 = - 3.46 0.08 + 3.54 = 3.62 95 % 2σ - 3.54 2σ + 3.54 Data Elements

More Related