Example – see Example 21.2 from course text Determine the quiescent output voltage of this circuit. Base current is small, so Emitter voltage V E = V B – V BE = 2.7 – 0.7 = 2.0 V Emitter current Since I B is small, collector current I C I E = 2 mA
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Determine thequiescent outputvoltage of thiscircuit
VE = VB – VBE = 2.7 – 0.7 = 2.0 V
Since IB is small, collector currentIC IE = 2 mA
Output voltage = VCC – ICRC = 10 - 2 mA 2.2 k = 5.6 V