Example – see Example 21.2 from course text

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# Example – see Example 21.2 from course text - PowerPoint PPT Presentation

Example – see Example 21.2 from course text Determine the quiescent output voltage of this circuit. Base current is small, so Emitter voltage V E = V B – V BE = 2.7 – 0.7 = 2.0 V Emitter current Since I B is small, collector current I C  I E = 2 mA

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Presentation Transcript
Example – see Example 21.2 from course text

Determine thequiescent outputvoltage of thiscircuit

Base current is small, so

Emitter voltage

VE = VB – VBE = 2.7 – 0.7 = 2.0 V

Emitter current

Since IB is small, collector currentIC  IE = 2 mA

Output voltage = VCC – ICRC = 10 - 2 mA 2.2 k = 5.6 V

A common-collector amplifier
• unity gain
• high input resistance
• low output resistance
• a very goodbuffer amplifier