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# MATH PROJECT - PowerPoint PPT Presentation

MATH PROJECT. DONE BY : LAILA HASSAN MOZA BADER HAMDA MUBARAK HOUR ESSA. TASK-1 PART-1. Write an algebraic expression for the charges under each option. Catering R us. All things catered 4U. 800+15x. 200+30x. PART-2.

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• DONE BY : LAILA HASSAN

• HAMDA MUBARAK

• HOUR ESSA

Write an algebraic expression for the charges under each option.

Catering R us

All things catered 4U

800+15x

200+30x

Recored the cost for each option for inviting 5,15,25,35,45 friends

R US - 800+15(5)=875

800+15(15)=1,025

800+15(25)=1175

800+15(35)=1325

800+15(45)=1475

4U- 200+30(5)=350

200+30(15)=650

200+30(25)=950

200+30(35)=1250

200+30(45)=1550

a) If Mohammed plans to invite 20 friends, which catering company should he choose? Show your work.

All thing catered 4U-:200+30(20)

=800AED

• catering R Us-: 800+15(20)

• =1,100AED

Mohammed should choose all thing catered 4U company.

b) If Mohammed plans to invite 50 friends, which catering company should he choose? Show your work.

Catering R Us -: 800+15(50)

=1.550AED

All things catered 4U-:200+30(50)

=1,700AED

Mohammed should choose all thing catered 4U company.

c) Find the exact number of persons that each of the two catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

The amount of each company will be 1,400AED for 40 persons.

Ans: 800+15x=200+30x

800-200=30x-15x

600/15=15x/15

X=40

200+30(40)=1,400 800+15(40) =1,400

PART-2 catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

Mohammed has 950 AED available to spend on his birthday party. How many friends can he invite under each of the catering options? Set up an equation for each option and solve it to find out how many friends (persons) that he can invite under each option.

Catering R Us :800+15x=950

15x=950-800

15x/15=150/15

X=10

10persons

All things catered 4U-:200+30x=950

30x=950-200

30x/30=750/30

X=25

25persons

PART-3 catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

Mohammed hates to waste food and beverages. He does not like to be embarrassed in front of his friends either for not providing enough to eat and drink. He determines that 40 persons plus or minus 10% is a good number. Write and solve an absolute value equation to find the maximum and minimum number of friends that Mohammed should invite to his party.

The maximum number of friends is 44

The minimum number of friends is 36

| x-40|=4

X-40=+4or-4

X-40=4

X-40=-4

X=4+40

X=-4+40

X=44

X=36

TASK-4 catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

PART-1

Three groups ,groups A,B,C of mohammed's friends decided to buy a watch as a memorable gift for his birthday contributed 1200AED in the ratio of 3:4:5.how much did each group contributed?

PART-2 catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

A) what is the percentage is the highest contribution with the respect to the total?

• the highest contribution is C

• 500/1200x100=41.7%

B) what is the percentage is the lowest contribution with the respect to the total?

B) the lowest contribution is A

300/1200x100=25%

TASK-5 catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

PART-1

Equations are used widely in our real-world life applications. Prepare a research about how solving equations helps us in different domains of our life.

The algebra activities on this page, make learning algebra easy and fun. Take the example in picture below.

BALANCED SCALED catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

For example, if I add a certain amount of weight to one side of the scale, to make it stay balanced, I know I need to add the same weight to the other side of the scale.

Guess what happens if you don’t add the same amount of weight to one side as you do to the other side. Well, take a look at the picture below if you’re wondering.

UNBALANCED SCALED catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

In Algebra, we always want the Scale to Stay Balanced. So in the above algebra example, too much weight was added to the right side of the scale. So the scale is not balanced anymore.

X+ catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

=

So the equation is x+5=9

There are two blocks on the left, one has a 5 in it and the other is empty.

Write an algebra equation for the balance, and

Determine what the resulting value of the variable, x is.

two blocks on the left, side must equal 9, the block on the right side of the balance scale.

3X=12 ; X=4 catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

6X=24; X=4

8X=64 ; X=8

THANK YOU catering companies can accommodate for the same amount. How much will the amount be? Show your complete solution.

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