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Rate Laws and Order of Reaction Read 6.3 p 372-378 Q 1-6 p 377

Rate Laws and Order of Reaction Read 6.3 p 372-378 Q 1-6 p 377. Concentration and Rate. Each reaction has its own equation that gives its rate as a function of reactant concentrations.  this is called its Rate Law

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Rate Laws and Order of Reaction Read 6.3 p 372-378 Q 1-6 p 377

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  1. Rate Laws and Order of ReactionRead 6.3 p 372-378Q 1-6 p 377

  2. Concentration and Rate Each reaction has its own equation that gives its rate as a function of reactant concentrations. this is called its Rate Law • A rate law is an equation expressing the rate of a reaction in terms of the [molar] of the species involved in the reaction.

  3. aA + bB  cC + dD • The rate is expressible as • rate = k[A]m[B]n • The powers m and n are kinetic orders, • A and B are the chemical substances • k is the rate constant, different values for each rxn

  4. Order of a Reaction • The “order” of a chemical reaction is the number of chemical [] terms upon which the rate depends • Rate = k[A] - first order rate; • the rate only depends on one [] term • Rate = k[A]2 - second order rate • Rate = k[A][B] - second order rate

  5. Concentration and Rate Compare Experiments 1 and 2:when [NH4+] doubles, the initial rate doubles.

  6. Concentration and Rate Likewise, compare Experiments 5 and 6: when [NO2-] doubles, the initial rate doubles.

  7. Concentration and Rate This equation is called the rate law, and k is the rate constant.

  8. Rate Laws • Exponents tell the order of the reaction with respect to each reactant. • This reaction is First-order to [NH4+] First-order to [NO2−] • The overall reaction order can be found by adding the exponents on the reactants in the rate law. • This reaction is second-order overall.

  9. Recall……………………….. • A rate law shows the relationship between the reaction rate and the concentrations of reactants. • For gas-phase reactants use Partial Pressure instead of [A]. • k is a constant that has a specific value for each reaction. • The value of k is determined experimentally. “Constant” is relative here- k is unique for each rxn k changes with T

  10. Temperature and Rate • Generally, as temperature increases, so does the reaction rate. • This is because k is temperature dependent.

  11. Determining Rxn Order from Experimental Data – Ex.1 • Four experiments were conducted to discover how the initial rate of consumption of BrO3- ions in the rxn varies as the concentrations of the reactants are changed. • Use the experimental data in the table below to determine the order of the reaction with respect to each reactant and the overall order. • Write the rate law for the rxn and determing the value of k.

  12. Data – Ex. 1

  13. Homework • Pg. 377 # 1-6 • Lab Exercise 6.4.1 The Sulfur Clock “determine the order of the reaction” p.404-405

  14. Review of Chemical Kinetics

  15. CH3NC CH3CN First-Order Processes Consider the process in which methyl isonitrile is converted to acetonitrile. How do we know this is a first order rxn?

  16. Reaction MechanismsRead 6.4 p 383-390 The sequence of events that describes the actual process by which reactants become products is called the reaction mechanism.

  17. Reaction Mechanisms • Reactions may occur all at once or through several discrete steps. • Each of these processes is known as an elementary reaction or elementary process.

  18. Reaction Mechanisms • The molecularity of a process tells how many molecules are involved in the process. • The rate law for an elementary step is written directly from that step.

  19. Multistep Mechanisms • In a multistep process, one of the steps will be slower than all others. • The overall reaction cannot occur faster than this slowest, rate-determining step.

  20. Slow Initial Step NO2(g) + CO (g) NO (g) + CO2(g) • The rate law for this reaction is found experimentally to be Rate = k [NO2]2 • CO is necessary for this reaction to occur, but the rate of the reaction does not depend on its concentration. • This suggests the reaction occurs in two steps.

  21. Slow Initial Step • A proposed mechanism for this reaction is Step 1: NO2 + NO2 NO3 + NO (slow) Step 2: NO3 + CO  NO2 + CO2 (fast) • The NO3 intermediate is consumed in the second step. • As CO is not involved in the slow, rate-determining step, it does not appear in the rate law.

  22. Fast Initial Step • The rate law for this reaction is found (experimentally) to be • Because termolecular (= trimolecular) processes are rare, this rate law suggests a two-step mechanism.

  23. Fast Initial Step • A proposed mechanism is {Step 1 is an equilibrium- it includes the forward and reverse reactions.}

  24. Fast Initial Step • [NO] [Br2] = [NOBr2]

  25. Questions • Q 2 p 390 • Q 1-3 p 391

  26. Unit Review • Chapter 5: Self Quiz Q 1-18 p 355 Q 2,4,6,9,14,16 • Chapter 6: Self Quiz 1-18 p 407, Q 4,7,910,13-16 p 408-409

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