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Acids ph buffers A2 chemistry. Using the post it notes write down the name of the species and whether each species round the room is an acid, base or alkali. H 3 O +. pka = -1.7 . H 2 O. pka = 15.7. HI. pka = -10. NH 4 +. pka = 9.2. Al 2 O 3. Na 2 O. SO 2. Ammonia. pka = 36 .
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Using the post it notes write down the name of the species and whether each species round the room is an acid, base or alkali
H3O+ pka = -1.7
H2O pka = 15.7
HI pka = -10
NH4+ pka = 9.2
Ammonia pka = 36
Complete the equations match up pka = 36
0.8L of 1M ethanoic acid reacted was titrated with 0.2L 1M NaOH. Calculate the pH of the solution. Ka = 1.76 x 10-5 Step 1. Work out moles of HA at start Step 2. Work out moles of base at start Step 3. Work out moles of HA that reacted with base – this is moles H+ Step 4. Minus moles of neutralised HA from initial acid to get the moles of HA Ka x [HA] = [H+]2 Step 5. Use equilibrium concentrations and put them in this equation Step 6. use pH = -log [H+]
0.25L of 1M ethanoic acid reacted was titrated with 0.25L 1M Ca(OH)2. Calculate the pH of the solution. Ka = 1.76 x 10-5 Step 1. Work out moles of HA at start Step 2. Work out moles of base at start Step 3. Work out moles of HA that reacted with base – this is moles H+ Step 4. Minus moles of neutralised HA from initial acid to get the moles of HA Ka x [HA] = [H+]2 Step 5. Use equilibrium concentrations and put them in this equation Step 6. use pH = -log [H+]
0.3L of 1M Methanoic acid reacted was titrated with 0.7L 1M Ca(OH)2. Calculate the pH of the solution. pKa = 3.77 Step 1. Work out moles of HA at start Step 2. Work out moles of base at start Step 3. Work out moles of HA that reacted with base – this is moles H+ Step 4. Minus moles of neutralised HA from initial acid to get the moles of HA Ka x [HA] = [H+]2 Step 5. Use equilibrium concentrations and put them in this equation Step 6. use pH = -log [H+]
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