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Check answers – a few were found to be wrong…possibly reword the definition/law questions

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##### Check answers – a few were found to be wrong…possibly reword the definition/law questions

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**Check answers – a few were found to be wrong…possibly**reword the definition/law questions**Powell**Augustine Head Brown Williams 100 100 100 100 100 200 200 200 200 200 300 300 300 300 300 400 400 400 400 400 500 500 500 500 500**Balloons X , Y and Z are hanging as shown. Balloon**X is positively-charged Balloon Y ____. A**What is**D. could be either negatively-charged or neutral?**The charge an electrophorus would gain if the base was made**out of glass. A**What is**Negative?**The reason that scraps of paper jump upand down and back up**when a charged plastic rod is brought near. A**What is**The pieces become polarized, are attracted to the rod, and jump up. When they touch, the charge is transferred to the piece, giving it the same charge. The attraction stops. When it touches ground, it looses its charge, allowing it to become polarized again ?**Explanation of the basic process of charging an**electroscope. A**What is**A charged object is touched to the ball of the electroscope. The charges are transferred and travel across the bars of the scope, causing it to repel ?**Explanation of how one’s hair raises when you touch the**Van de Graaff generator. A**What is**Negative charges travel from the Van de Graaff generator onto one’s body as they try to get as they try to spread out. When on your hair, they cause it to raise up as they try to repel as far as possible ?**The magnitude of the force of a +25µC charge on a -50µC**charge 20 cm away. +25µC -50µC 22cm A**k Q1Q2**F = r2 What is 2.81 x 102 N ? Nm2 9x109 (50 x 10-6 C) (25 x 10-6 C) C2 = 2.81 x 102 N (.20 m)2**The magnitude of the force 10 electrons would apply on 4**protons at a distance of 1µm. Hint…qe=1.6x10-19 C A**What is**9.22 x 10-15 N ? Nm2 9x109 [4(1.6 x 10-19 C)] [10(1.6 x 10-19 C)] C2 = 9.22 x 10-15 N (1 x 10-6 m)2 k Q1Q2 F = r2**The force applied on the farthest right charge by the other**two charges. +8µC -6µC +5µC 7mm 3mm A**What is**2.64 x 104 N left ? k Q1Q2 F = r2 Nm2 9x109 (8 x 10-6 C) (5 x 10-6 C) C2 F13 = = 3.6 x 103 N (10 x 10-3 m)2 Nm2 9x109 (6 x 10-6 C) (5 x 10-6 C) C2 F23 = = 3 x 104 N (3 x 10-3 m)2 F23 + F13 = 2.64 x 104 left**The number of electrons you would need to put on**electrostatic flying boots to make a 70kg person hover at a height of 2 m above a charge of -50 mC. Ahhh.. I’m flying! A**What is**2.38 x 1012? k Q1Q2 F = r2 Nm2 9x109 (-50 x 10-3 C) [n(-1.6 x 10-19 C)] C2 F = 70kg (9.81 m/s2) = (.20 m)2 n = 2.38 x 1012**The force on the orange charge.**+4.6 C -5.4 C 2.5 m + 7.2 C 4 m 2 m 5 m -5.4 C +4.6 C A**What is**0 N ? k Q1Q2 F = r2 Diagonal forces cancel each other out, resulting in a net force of 0N on the orange charge.**What is**The law of conservation of electric charge ?**What is**The Charge of a proton ?**The charging of an isolated conducting object by grounding**it while a charged body is nearby. A**What is**Induction ?**The force F exerted on a tiny positive test charge placed**divided by the magnitude of the test charge. A**What is**Electric Field, E ? F E = q**What is**A dipole ?**The charge of the orange charge**Followed by The charge of the blue charge A**What is**Positive (orange), negative (blue) ?**Charge on the blue charge**|Q|=4.7 x 10-4 C A**What is**-3.5 x 10-4 C ? 4.7 x 10-4 C 8 lines = ? 6 lines |Q|=4.7 x 10-4 C**The number of lines that should point outwards from the**orange plate. ? ? BE CAREFUL!!!! A**What is**0 ? Follow up question How many lines should point inwards? 8 lines ? = 8 charges 6 charges**Charges of point charges in order**(orange, blue, green, white) A**What is**- - + + ? Orange Blue Green White**Minimum of 2 errors in the following drawing, with**explanations of error. 2 C 2 C A**What are**Wrong direction of field lines (should go from positive to negative) and Wrong number of field lines (should be equal as charge is equal) ?**E-Field at X below**12 C 15m A**What is**6 x 108 N/C left ? k Q E = r2 Nm2 9x109 (12 C) C2 = 6 x 108 N/C (15 m)2 12 C 15m**Approximate location of E=0 N/C on line between orange and**blue charge 12 C 24 C 15m A**What is**Somewhere between orange and mid point (7.5m to the right of orange) ? k Q E = r2 12 C 24 C 15m**The E-Field at the X**12 C 24 C 15m 10 m A**k Q**What is 2.33 x 109 N/C right ? E = r2 E24C E12C Nm2 9x109 (24 C) C2 = 2.16 x 109 N/C (10 m)2 Nm2 9x109 (12 C) C2 = 1.7 x 108 N/C (25 m)2 12 C 24 C 15m 10 m**The letter which denotes the location with the greatest**magnitude of E-Field B C D A 4m 3m 2m 1m Q=24C Q=18C Q=7C Q=1.5C A