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Computer Architecture Discussion

Computer Architecture Discussion. Lecture # 2 MIPS Programming. MIPS Arithmetic Instruction. MIPS assembly language arithmetic statement add $t0, $s1, $s2 sub $t0, $s1, $s2 Each arithmetic instruction performs only one operation

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Computer Architecture Discussion

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  1. Computer Architecture Discussion Lecture # 2 MIPS Programming

  2. MIPS Arithmetic Instruction • MIPS assembly language arithmetic statement add $t0, $s1, $s2 sub $t0, $s1, $s2 • Each arithmetic instruction performs only one operation • Each arithmetic instruction specifies exactly three operands destination  source1 op source2 • Those operands are contained in the datapath’s register file ($t0, $s1,$s2) • Operand order is fixed (destination first)

  3. Compiling More Complex Statements • Assuming variable b is stored in register $s1, c is stored in $s2, and d is stored in $s3 and the result is to be left in $s0, what is the assembler equivalent to the C statement h = (b - c) + d sub $t0, $s1, $s2 add $s0, $t0, $s3

  4. Accessing Memory • MIPS has two basic data transfer instructions for accessing memory lw $t0, 4($s3) #load word from memory sw $t0, 8($s3) #store word to memory (assume $s3 holds 2410) • The data transfer instruction must specify • where in memory to read from (load) or write to (store) – memory address • where in the register file to write to (load) or read from (store) – register destination (source) • The memory address is formed by summing the constant portion of the instruction and the contents of the second register 28 32

  5. . . . . . . A[3] $s3+12 A[2] $s3+8 A[1] $s3+4 A[0] $s3 Compiling with Loads and Stores • Assuming variable b is stored in $s2 and that the base address of array A is in $s3, what is the MIPS assembly code for the C statement A[8] = A[2] - b lw $t0, 8($s3) sub $t0, $t0, $s2 sw $t0, 32($s3)

  6. MIPS Instructions, so far

  7. Review: Naming Conventions for Registers 0 $zero constant 0 (Hdware) 1 $at reserved for assembler 2 $v0 expression evaluation & 3 $v1 function results 4 $a0 arguments 5 $a1 6 $a2 7 $a3 8 $t0temporary: caller saves . . . (callee can clobber) 15 $t7 16 $s0 callee saves . . . (caller can clobber) 23 $s7 24 $t8temporary (cont’d) 25 $t9 26 $k0 reserved for OS kernel 27 $k1 28 $gp pointer to global area 29 $sp stack pointer 30 $fp frame pointer 31 $ra return address (Hdware)

  8. [R] format and [I] format

  9. 000000 10001 10010 01000 00000 100000 op rs rt rd shamt funct Machine Language - Arithmetic Instruction • Instructions, like registers and words of data, are also 32 bits long • Example: add $t0, $s1, $s2 • registers have numbers $t0=$8, $s1=$17, $s2=$18 • Instruction Format:

  10. op rs rt rd shamt funct MIPS Instruction Fields • op • rs • rt • rd • shamt • funct 6 bits 5 bits 5 bits 5 bits 5 bits 6 bits = 32 bits opcode indicating operation to be performed address of the first register source operand address of the second register source operand the register destination address shift amount (for shift instructions) function code that selects the specific variant of the operation specified in the opcode field

  11. 35 18 8 24 100011 10010 01000 0000000000011000 op rs rt 16 bit number Machine Language - Load Instruction • Consider the load-word and store-word instructions, • What would the regularity principle have us do? • New principle: Good design demands a compromise • Introduce a new type of instruction format • I-type for data transfer instructions • previous format was R-type for register • Example: lw $t0, 24($s2)

  12. 43 18 8 24 101011 10010 01000 0000000000011000 op rs rt 16 bit number Machine Language - Store Instruction • Example: sw $t0, 24($s2) • A 16-bit address means access is limited to memory locations within a region of 213 or 8,192 words (215 or 32,768 bytes) of the address in the base register $s2

  13. lw 35 19 8 8 sub 0 8 18 8 0 34 sw 43 19 8 32 Assembling Code • Remember the assembler code we compiled last lecture for the C statement A[8] = A[2] - b lw $t0, 8($s3) #load A[2] into $t0 sub $t0, $t0, $s2 #subtract b from A[2] sw $t0, 32($s3) #store result in A[8] Assemble the MIPS code for these three instructions

  14. Beyond Numbers • Most computers use 8-bit bytes to represent characters with the American Std Code for Info Interchange (ASCII)

  15. Book Exercises • Book exercises solved: 2,3,4,6,13,20 • and some exercises for R & I format

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