340 likes | 738 Views
Kendriya Vidyalaya IFFCO,Gandhidham Maths Project On Binary Operations. DETAILS. Name : Swetha,Sumouly,Prachi,Sejal. Standard : XII Subject : Mathematics Topic : Binary Operations Teacher-In-charge : Geetha Ma’am School : KV,IFFCO Gandhidham. Year : 2010-2011. ACKNOWLEDGEMENT.
E N D
Kendriya Vidyalaya IFFCO,GandhidhamMaths ProjectOn Binary Operations
DETAILS • Name: Swetha,Sumouly,Prachi,Sejal. • Standard: XII • Subject: Mathematics • Topic: Binary Operations • Teacher-In-charge: Geetha Ma’am • School: KV,IFFCO Gandhidham. • Year: 2010-2011
ACKNOWLEDGEMENT We hereby extend our sincere gratitude to our teacher/mentor Madam Geetha for alloting such an interesting project,to our Principal Mrs.Sangeeta Gutain , for her co-operation and guidance,to our parents for their help,concern and blessings.We gratefully acknowledge the valuable and precious contributions and support of the above mentioned people in making this project a SUCCESS………..
INTRODUCTION • BINARY OPERATION: A binary operation * on a set A is a function from AXA→A. We denote it by *(a,b)=a*b.+,-,*,/,these operations between two operands result in binary operation.
E.g. A binary operation on ‘R’ +:R×R→R is given by (a,b)→a+b E.g. A binary operation of division is not possible on ‘R’ because ‘R’ includes 0 also and in ‘a/b’ form if ‘b’ is zero then product becomes not defined.
COMMUTATIVE BINARY OPERATION • COMMUTATIVE OPERATION A binary operation * on the set x is called commutative if a*b=b*a for all a,b ε X. E.g.5+2=2+5, where a=5,b=2 and * is operation (+), this satisfies the condition of a+b=b+a,i.e 7=7.
E.g.Show that * is a function from RXR→R defined by a*b=a+2b is not commutative? Solution: a*b=a+2b (given) b*a=b+2a, but it is clear that a*b ≠ b*a , that means a+2b ≠ b+2a. let us take a=2 and b=3 a+2b= 2+2(3)=8,but b+2a=3+2(2)=7, it is clear that a+2b ≠ b+2a as 8 ≠ 7. Hence proved…
ASSOCIATIVE BINARY OPERATION • ASSOCIATIVE OPERATION: A binary operation * : AXA →A is said to be associative if (a*b)*c=a*(b*c) for all a,b,c ε A. E.g. (8+5)+2=8+(5+2),a=8,b=5 & c=2 and * is operation(+),this satisfies the condition (a*b)*c=a*(b*c) implies 15=15.
E.g.Show that * is a function from RXR→R defined by a*b=a+2b is not associative? Solution: (a*b)*c=(a+2b)*c (given) a*(b*c)=a*(b+2c) but it is clear that (a*b)*c ≠ a*(b*c) that means (a+2b)+c ≠ b+2a. let us take a=8 ,b=5 and c=3 (a+2b)*c= (8+2(5))*3=24, but a+(b+2c)=8*(5+2(3))=30 it is clear that (a+2b)*c ≠ a*(b+2c) as 24 ≠ 30. Hence proved…
IDENTITY ON A BINARYOPERATION • IDENTITY OPERATION: A binary operation * : AXA →A ,an element eεA if it exists, is called identity for operation *,if a*e=a=e*a for all aεA. • ADDITIVE IDENTITY: zero is identity for the addition operation. • MULTIPLICATIVE IDENTITY: one is identity for the multiplication operation.
E.g.Show that zero and one are additive and multiplicative identity on R. But there is no identity element for subtraction and division. Solution: a+0=0+a= a, shows 0 is additive identity and ax1=1xa= a , shows 1 is multiplicative identity. but a-e=e-a= a , there is no such value for e. a/e=e/a=a , there is no such value for e. Hence proved…
INVERTIBILITY OF A BINARY OPERATION • INVERTIBLE BINARY OPERATION: A binary operation * : AXA →A ,with the identity element in A , an element a ε A is said to be invertible with respect to the operation*, if there exists an element b in A such that a*b=e=b*a and b is called the inverse of a and is denoted by a-1.
E.g.Show that –a and 1/a(a!=0) are the inverse of a for addition(+) and multiplication operation(x) on R. Solution: As a+(-a)=a-a=0 & (-a)+a=0,shows –a is the inverse of a for addition. Similarly, for a!=0, a x (1/a) = 1 & (1/a) x a = 1, shows 1/a is the inverse of a for multiplication. Hence proved…
BIBLIOGRAPHY NCERT MATHEMATICS TEXTBOOK FOR CLASS XII… PART I