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ConcepTests in Chemical Engineering Thermodynamics Unit 2: Generalized Analysis of Fluid Properties Note: Slides marked with JLF were adapted from the ConcepTests of John L. Falconer, U. Colorado. Cf. Chem. Eng. Ed. 2004,2007. Day 22 MRs.

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ConcepTests in Chemical Engineering ThermodynamicsUnit 2: Generalized Analysis of Fluid PropertiesNote: Slides marked with JLF were adapted from the ConcepTests of John L. Falconer, U. Colorado. Cf. Chem. Eng. Ed. 2004,2007

slide2

Day 22 MRs

22.1. Transform the expressions below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if it not associated with a derivative. (S/V)T

(a) (P/V)S (b) (T/V)U (c) (U/T)V (d) (P/T)V

slide3

Day 22 MRs

22.2. Transform the expressions below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if it not associated with a derivative. (S/P)V

(a) Cv(T/P)V/T (b) (T/V)U(c) (U/T)V(d) (P/T)V

slide4

Day 22 MRs and EOSs

22.3. Transform the expressions below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (V/S)P

(a) Cv(T/P)V/T (b) T(V/T)P/Cp(c) (T/P)S(d) -(V/T)P

slide5

Day 22 MRs and EOSs

22.4. Transform the expressions below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (G/S)P

(a) V(P/S)V/T(b) TS(V/T)P/Cv(c) -TS/Cp(d) -S(T/S)P

22 5 use the vdw eos to describe the following derivative t z t v fyi vdw eos is z 1 1 b r a r rt

Day 22 MRs and EOSs

22.5. Use the vdW EOS to describe the following derivative. -T(Z/T)VFYI vdw EOS is: Z = [1/(1-br)] – [ar/RT]

(a) [1/(1-br)] (b) [1/(1-br)2] (c) –[ar/RT](d) [ar/RT2]

slide7

QikQiz2.1

Q2.1.1. Transform the expression below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (A/P)V

(a) -S(T/P)V(b) Cp(T/P)V(c) TS/P(d) -VS(T/V)P /Cp

slide8

QikQiz2.1

Q2.1.2. Transform the expression below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (H/P)T

(a) V(b) V-T(V/T)P(c) -T(S/P)T+V(d) -T(P/T)V - P

slide9

QQ2.1

Q2.1.3. The following strange equation of state has been proposed: P = (RT/V1.5) - a/T1.3where a is a constant. Derive an expression for (P/T)V

(a) RT2/(2*V1.5) + a/(0.3*T0.3)(b) (R/V1.5) – 1.3a/T2.3(c) -1.5(R/V2.5) – 1.3a/T2.3(d) (R/V1.5) + 1.3a/T2.3

slide10

Day 24 MRs and EOSs

24.1. Transform the expression below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (H/S)V

(a) T(1+ V(P/T)V/Cv )(b) VS(T/V)P/Cv(c) TS/Cp(d) -VS(T/V)P /Cp

slide11

Day 24 MRs and EOSs

24.2. Transform the expression below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (H/P)V

(a) Cv(T/P+ T(V/P)T/V )(b) VS(T/V)P/Cv(c) TS/P(d) Cp(T/ P )V + [V-T(V/T)P]

slide12

Day 24 MRs and EOSs

24.3. Use the PR(1976) EOS to describe the following derivative. -T(Z/T)VFYI: PR EOS is on P204 (Eq. 6.16-6.19)

(a)(b) (c) (d)

slide14

Day 25 MRs and EOSs

25.1. Transform the expression below in terms of Cv, T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (H/T)P

(a) Cv+ T(P/T)V(V/T)P(b) Cv+ [T(P/T)V –P ](V/T)P(c) Cp(d) (U/ T)P + P(V/T)P]

slide15

Day 25 MRs and EOSs

25.2. Transform the expression below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (A/V)T

(a) (U/V)T - T (S/V)T(b) [(P/T)V – P] + (P/T)V(c) -P(d) –T (P/T)V

slide19

Day 27 QikQiz2.2

Q2.2.1. Transform the expression below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (G/S)P

(a) - V(T/V)P(b) PS(T/P)V/Cp(c) –ST/Cp(d) (H/S)P –T –S(T/S)P

slide20

Day 27 QikQiz2.2

Q2.2.2. Transform the expression below in terms of Cp, Cv , T, P, and V. Your answer may include absolute values of S if not associated with a derivative. (P/S)G

(a) -T(V/T)P(b) [-(V/T)P – CpV/(ST)]-1(c) –(ST/Cp)(V/T)P + V(d) -(T/V)P

28 1 why do we write our equation of state models as z t v or a t v when what we want is v t p
28.1. Why do we write our Equation of State models as Z(T,V) or A(T,V) when what we want is V(T,P)?

Day 28 EOSs

  • because dA = PdV – SdT is more “fundamental.”
  • because pressure is a sum of forces, but density is not a sum of pressures.
  • to make life difficult for poor students.
  • because V(T,P) is not a function.
slide25

Day 28 EOSs

28.3.True or false____The compressibility factor Z is always less than or equal to unity.____The critical properties Tc and Pc are constants for a given compound.____A steady-state flow process is one for which the velocities of all streams may be assumed negligible.____The temperature of a gas undergoing a continuous throttling process may either increase or decrease across the throttling device, depending on conditions.

(a) FTFT(b) TTTF (c) TFTF(d) FFFT

29 1 at 2 25 gal and 0 692 g cm3 the price of gasoline in kg is closest to

Day 29 HW

29.1. At 2.25$/gal, and 0.692 g/cm3, the price of gasoline in $/kg is closest to:

(a) 0.2(b) 0.4(c) 0.6(d) 0.8

slide28

Day 29 HW

29.3. Referring to problem 6.21, the resulting equation of state at the given conditions has the value of Z = ___

(a) 0.5(b) 1.5(c) 2.5(d) 3.5

33 3 which of the following would indicate a small acentric factor

Day 33

33.3 Which of the following would indicate a small acentric factor?

(a) high molecular weight(b) a noble gas(c) strong hydrogen bonding(d) a spherical molecule with strong hydrogen bonding

slide32

Day 33

33.4. “Boiling” is the process of transforming a liquid into a vapor. “Sublimation” is the process of transforming a solid into a vapor. For carbon dioxide, the heat of sublimation (HV-HS) is roughly 24750 J/mole at the triple point temperature and pressure of -56.6C and 5.27 bars. Estimate the sublimation temperature at 0.5 bar.

(a) 240(b) 225(c) 210(d) 195

slide33

QikQiz2.3

Q2.3.1 Vapor ethylene oxide is compressed from 25C and 1 bar to 125C and 20 bar. The change in entropy (J/mol-K) is:

(a) 8(b) 10(c) -12(d) -16

slide34

QikQiz2.3

Q2.3.2. Determine the work (kW) required to continuously compress reversibly and adiabatically 0.5kg/min of ethylene oxide from 25C and 1 bar to 20 bar. The temperature (K) exiting the compressor is:

(a) 425(b) 450(c) 470(d) 500

slide35

QikQiz2.3

Q2.3.3. Determine the work (kW) required to continuously compress reversibly and adiabatically 0.5kg/min of ethylene oxide (MW=40) from 25C and 1 bar to 20 bar.

(a) 1.8(b) 2.0(c) 200(d) 9000

slide36

QikQiz2.3

Q2.3.4. Ethylene oxide (MW=40) enters a throttle as saturated liquid at 2MPa and exits at 1bar. Determine the quality (%) at the exit.

(a) 45(b) 35(c) 25(d) 15

slide38

QikQiz2.4

Q2.4.1. Derive the simplest form of the Gibbs energy departure function for the following equation of state: Z = 1 + 4b/(1-2b) - a/RT1.7

(a) –ln(1-b)- a/RT1.7 + Z – 1 - lnZ(b) -2ln(1-2b)- a/RT1.7 + Z – 1 - lnZ(c) -2ln(1-2b) + 1.7a/RT2.7 + Z – 1 - lnZ(d) -4ln(1-2b)- a/RT1.7 + Z – 1 - lnZ

slide41

QikQiz2.4

Q2.4.4. “Boiling” is the process of transforming a liquid into a vapor. “Sublimation” is the process of transforming a solid into a vapor. For carbon dioxide, the heat of sublimation (HV-HS) is roughly 24750 J/mole at the triple point temperature and pressure of -56.6C and 5.27 bars. Estimate the sublimation temperature at 0.5 bar.

(a) 240(b) 225(c) 210(d) 195

qq2 5 1 for the scott eos evaluate
Qq2.5.1. FOR the Scott EOS:Evaluate

QikQiz2.5

(a)(b) (c) (d)

slide44

QikQiz2.5

Q2.5.3. A power cycle is to run on bromine operating at 0.1MPa in the condenser and 6MPa in the boiler. Estimate the Carnot efficiency.

(a) 0.3(b) 0.4(c) 0.5(d) 0.6

slide45

QikQiz2.5

Q2.5.4. A Rankine cycle is to operate on bromine operating at 0.1MPa in the condenser and 6MPa in the boiler. Estimate the turbine work (kJ/mol).

(a) 18(b) 12(c) 6(d) 3

slide46

QikQiz2.5

Q2.5.5. A Rankine cycle is to operate on bromine operating at 0.1MPa in the condenser and 6MPa in the boiler. Estimate the Rankine efficiency.

(a) 0.3(b) 0.4(c) 0.5(d) 0.6