1 / 13

Prof. David R. Jackson ECE Dept.

ECE 2317 Applied Electricity and Magnetism. Spring 2014. Prof. David R. Jackson ECE Dept. Notes 15. Potential Integral Formula. This is a method for calculating the potential function directly, without having to calculate the electric field first.

calida
Download Presentation

Prof. David R. Jackson ECE Dept.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. ECE 2317 Applied Electricity and Magnetism Spring 2014 Prof. David R. Jackson ECE Dept. Notes 15

  2. Potential Integral Formula This is a method for calculating the potential function directly, without having to calculate the electric field first. • This is often the easiest way to find the potential function (especially when you don’t already have the electric field calculated). There are no vector calculations involved. • The method assumes that the potential is zero at infinity. (If this is not so, you must remember to add a constant to the solution.)

  3. Potential Integral Formula (cont.) Point charge formula: r(x, y, z) z R From the point charge formula: y x Integrating, we obtain the following result:

  4. Potential Integral Formula (cont.) Summary for all possible types of charge densities: Note that the potential is zero at infinity (R ) in all cases.

  5. Example z r = (0, 0, z) R a y x l0[C/m] Find (0, 0, z) Circular ring of line charge Note: The upper limit must be larger than the lower limit, to keep dl positive.

  6. Example (cont.) For (This agrees with the point charge formula.)

  7. Example z Find (0, 0, z) r = (0, 0, z) R a y a a x v0[C/m] Solid cube of uniform charge density The integral can be evaluated numerically.

  8. Example (cont.) z (0, 0, z) [V] a y a x a h [m] Result from Mathcad

  9. Example (cont.) 2.0 Face of cube z 1.5 (0, 0, z) [V] 1.0 a y 0.5 a x 0 a 1.5 1.0 0.5 2.0 h [m] Result from Mathcad

  10. Limitation of Potential Integral Method This method always works for a “bounded” charge density; that is, one that may be completely enclosed by a volume. • For a charge density that extends to infinity, the method might fail because it may not be possible to have zero volts at infinity. • This will happen when there is an infinite voltage drop going to infinity.

  11. Example of Limitation Can we put the reference point at infinity? z Assume that  () = 0 Try integrating the electric field: l0[C/m] y r  x  The integral does not exist! Infinite line charge

  12. Example of Limitation (cont.) z l0[C/m] z R y r  x  Since we cannot put the reference point at infinity, the potential integral method will fail. The integral does not converge! Infinite line charge

  13. Example of Limitation (cont.) z The field-integration method still works: l0[C/m] (From Notes 14) y r  Note: We can still use the potential integral method if we assume a finite length of line charge first, and then after solving the problem let the length tend to infinity. (This will be a homework problem.) b x R( =b) Infinite line charge

More Related