1 / 22

300 likes | 642 Views

6.1 Graphing Quadratic Functions. Parabola Axis of symmetry Vertex. A Quadratic function. Parts of the Quadratic function. CONSTANT TERM. A Quadratic function. The graph of a Quadratic function is called a parabola. Parabola are Symmetrical. Axis of Symmetry, splits it down the middle.

Download Presentation
## 6.1 Graphing Quadratic Functions

**An Image/Link below is provided (as is) to download presentation**
Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.
Content is provided to you AS IS for your information and personal use only.
Download presentation by click this link.
While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.
During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

**6.1 Graphing Quadratic Functions**Parabola Axis of symmetry Vertex**A Quadratic function**Parts of the Quadratic function. CONSTANT TERM**A Quadratic function**The graph of a Quadratic function is called a parabola.**Parabola are Symmetrical**Axis of Symmetry, splits it down the middle**Parabola are Symmetrical**Points reflect across the axis of symmetry**Parabola are Symmetrical**The equation for the axis symmetry is**The y – Intercept of a parabola**If x = 0, then c is the y intercept**The Vertex of the Parabola**The Vertex is a point at the highest or lowest point of the graph of a parabola. The Vertex is on the axis of symmetry, so its x coordinate is found by**Now that you have x of the Vertex how do you find the y**x = 1**How can you tell if the Vertex is the highest or lowest**point. It all depends on “a”. If a > 0, the parabola If a<0, the parabola is opens upward. opens downward**The Maximum or Minimum value is the y value of the vertex**If the vertex is ( -3, 1), of f(x)= x2 + 6x + 10, then the minimum value is 1. Since the parabola is opening upward it is the minimum.**How to graph the parabolaf(x) = 2- 4x + x2**Rewrite the function. f(x) = x2 -4x + 2 Find the y intercept: f(0) = 02 -4(0) + 2 = 2 (0, 2) Find the vertex: a = 1, b= -4**How to graph the parabolaf(x) = 2- 4x + x2**Start a table using number higher and lower then 2, from the vertex. Plot points**How to graph the parabolaf(x) = 2- 4x + x2**Connects the points.**Graph the function. Show the y intercept, axis of symmetry**and vertex f(x) = -x2 + 2x + 3**Graph the function. Show the y intercept, axis of symmetry**and vertex f(x) = -x2 + 2x + 3 Does the graph open up or down? What are a , b and c?**Graph the function. Show the y intercept, axis of symmetry**and vertex f(x) = -x2 + 2x + 3 Does the graph open up or down? Down What are a , b and c? a = -1 b = 2 c = 3, so the y intercept is (0,3)**Graph the function. Show the y intercept, axis of symmetry**and vertex f(x) = -x2 + 2x + 3 axis of symmetry is x = 1 What are a , b and c? a = -1 The vertex is b = 2 c = 3**Graph the function. Show the y intercept, axis of symmetry**and vertex f(x) = -x2 + 2x + 3 Plot the points**Graph the function. Show the y intercept, axis of symmetry**and vertex f(x) = -x2 + 2x + 3 Connect the points**Homework**Page 291 # 15, 19, 23, 25, 33 – 43 odd**Homework**Page 291- 292 # 16, 22, 26, 32 - 42 even, 46, 47

More Related