1 / 19

# Exponential Function 5 Item MCQ - PowerPoint PPT Presentation

Exponential Function 5 Item MCQ. ANSILUZ H. BETCO San Bartolome High School. NEXT. Directions. Read and analyze the following questions properly. Click on the correct answer. BACK. NEXT. 1 . Which of the following define an exponential function?. BACK. NEXT.

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about ' Exponential Function 5 Item MCQ' - aubrey-cash

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript

### Exponential Function5 Item MCQ

ANSILUZ H. BETCO

San Bartolome High School

NEXT

Read and analyze the

following questions

properly. Click on the

BACK

NEXT

1. Which of the following define an exponential function?

BACK

NEXT

a) 2x2 + 3x – 6= 8

b) 2/3 m – 5 = 15

c) y = 2x + 1

d) p3 + 2p -3 = 0

Feedback to Q1

BACK

Definition:

→ If a>0 and a ≠ 1,then the exponential function with the base a is a function defined by f(x) = ax, where x is any real numbers.

→ therefore y= 2x +1 is the only equation wherein the exponent x vary.

NEXT

2) Which of the following graphs represent an exponential function?

a)b)

d)

c)

BACK

NEXT

Feedback to Q2

BACK

The graph of y = ax is upward-sloping, and

increases faster as x increases. The graph

always lies above the x-axis but can get

arbitrarily close to it for negative x; thus,

the x-axis is a horizontal asymptote. The

slope of the graph at each point is equal

to its y coordinate at that point.

NEXT

3) Solve for x: 93x = (1/3)5-x

a) x = 1

b) x = -1

c) x = 2

d) x = -2

BACK

NEXT

Feedback to Q3

BACK

3) 93x = (1/3)5-x

• Solution

93x = (1/3)5-x

32(3x)= 3-1(5-x) change the equation with same base

6x = -5+x bring down the exponents

5x = -5 solve for x

x = -1 answer

NEXT

4) A certain city has a population of 20000 and a growth rate of 3.5%.What will be the expected population after 3 years?

• 24,145

• 23,501

• 23,219

• 22,174

BACK

Feedback to Q4

BACK

The Exponential Growth is in the form

Y = P( 1 + r)xwhere P = original number

r = rate of change

x = unit of time

y = total number after x years

So, P = 20000 r = 3.5% or 0.035 t = 3 years

Substitute Y = P( 1 + r)x

= 20,000 (1 + .035)3

= 20,000 (1.035)3

= 20,000 (1.1087)

= 22,174 expected population after 3 yrs

NEXT

5) If a car depreciates at an annual rate of 15%, how much would be its value at the end of two years if its cost is \$450,000 when new? a) \$325,125 b) \$276,356c) \$315,134d) \$412,300

BACK

Feedback to Q5

BACK

The Exponential Decay is in the form

Y = P( 1 - r)xwhere P = original amount

r = rate of change

x = unit of time

y = total amount after x years

So, P= \$450,000 r = 15% or 0.15 t= 2 years

Substitute Y = P( 1 - r)x

= 450,000 (1 - .15)2

= 450,000 (0.85)2

= 450,000 (0.7225)

= \$325,125 amount of car after 2 years

NEXT

i'm sorry

Try again !

i'm sorry

Try again !