KONSTRUKSI BALOK GERBER

1 / 5

# KONSTRUKSI BALOK GERBER - PowerPoint PPT Presentation

KONSTRUKSI BALOK GERBER. S=sendi/engsel Konstruksi ABSC dibagi 2 bagian yaitu: 1.SC= S=sendi dan C=roll 2.ABS=A=Engsel, B Roll, S=Bebas A B S C

I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.

## PowerPoint Slideshow about 'KONSTRUKSI BALOK GERBER' - arsenio-sutton

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
KONSTRUKSI BALOK GERBER
• S=sendi/engsel
• Konstruksi ABSC dibagi 2 bagian yaitu:
• 1.SC= S=sendi dan C=roll
• 2.ABS=A=Engsel, B Roll, S=Bebas
• A B S C
• S I C
• A II B
Perhitungan
• A 6 T B S 5T C
• 2m 4m 1m 3m 2m
• 5t
• S C
Balok SC
• Syarat Kesetimbangan
• V=0 Vs+Vc =5t
• Ms=0
• 5.3-Vc.5 =0
• 15-5Vc=0
• 15=5Vc
• Vc=3t
• Vs+Vc=5t
• Vs+3=5t
• Vs=2t
• Kontrol
• Mc=0
• Vs.5-5.2=0
• 2.5-5.2=0 (ok)
Balok ABS
• A 6T B 2T
• S
• 2m 4m 1m
• V=0 VA+VB=6+2= 8 t
• MA=0
• 6.2-VB+2.7=0
• VB=4 .1/3
• MB=0
• VA.6-6.4+2.1=0
• 6VA=24-2=22
• VA=22/6
• VA=3.2/3
• Kontrol= VA+VB=8 T
Konstruksi 3 sendi
• Portal simetris Portal tak simetris

S S

HB

B

HA VB

A HA HB B A

VA VB VA