Chemistry 20 Mole Conversions. What is a Mole?. A term of measurement A counting number Similar to saying 1 dozen = 12 things Avogadro's Number (N A ) 6.02 x 10 23 items A VERY LARGE NUMBER!!!. = 1 mole.
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6.02 x 1023 items
A VERY LARGE NUMBER!!!
= 1 mole
Mass In Grams
Carbon, C = 12.01 g/mol
Phosphorus, P = 30.97 g/mol
What is the Molar Mass of:
Na = 22.99g/molCl= 35.45g/mol
NaCl = 22.99g/mol + 35.45g/mol = 58.44g/mol
C6= 6(12.01g/mol) H12 = 12(1.01g/mol) O6 = 6(16.00g/mol)
C6H12O6= 6(12.01g/mol) +12(1.01g/mol) 6(16.00g/mol)
= 180.18 g/mol
Sodium bicarbonate, NaHCO size of Earth 1m deep in green peas3:
Na= 22.99g/mol H=1.01g/mol C=12.01g/mol
O = 3(16.00g/mol)
NaHCO3= 22.99g/mol + 1.01g/mol + 12.01g/mol + 3(16.00g/mol)
A grade eleven chemistry student has 3.00 g of boron tribromide (BBr3). How many moles of BBr3 is this?
Molar mass of BBr3 = 10.81 + 3(79.90) = 250.51g/mol
3.00g BBr3 x1mole = 0.0120 mole BBr3
REMEMBER SIG FIGS!
If I have 50.0g of calcium chlorate (CaClO size of Earth 1m deep in green peas3)2 how many moles do I have?
Molar Mass (CaClO3)2 =
2(40.08) + 2(35.45) + 6(16.00) = 247.06 g/mol
50.0g (CaClO3)2 x 1 mole = 0.202 mole (CaClO3)2
Determine the mass of size of Earth 1m deep in green peasthe following amount:
6.94 mol barium chloride (BaCl2)
Molar Mass BaCl2 = 137.33 + 2(35.45) = 208.23 g/mol
6.94 molBaCl2 x 208.23 g = 1.45 x 103 g BaCl2
Remember only 3 sig figs
6.02 x 1023 molecules or atoms or formula units
If a chemist is experimenting with 5 700 000 000 atoms of lead how many moles is she dealing with?
Avogadro’s number = 6.02 x 1023 atoms
5 700 000 000 atoms Pb x 1 mole = 9.5 x 10-15mol
6.02 x 1023 atoms
2 sig figs
2 sig figs
How many moles is in 2.97 x 10 size of Earth 1m deep in green peas25 atoms of Vanadium?
2.97 x 1025 atoms of V x 1 mole
6.02 x 1023 atoms
= 49.3 moles of V
Determine the number of molecules in the following: size of Earth 1m deep in green peas
1.01 mol Bi x 6.02 x 1023 atoms
= 6.08 x 1023atoms of Bi
b) 2.5 moles of size of Earth 1m deep in green peasmanganese
2.5 molMnx 6.02 x 1023atoms
= 1.5 x 1024atoms of Mn
If the students in a chemistry 20 class have size of Earth 1m deep in green peas
7.66 x 1019 molecules of hydrogen peroxide, H2O2, how many moles do they have?
7.66 x 1019 molecules x 1 mole 6.02 x 1023 molecules
= 1.27 x 10-4 molecules of H2O2
Litres of Gas at STP
Determine the volume, in liters, occupied by 0.030 moles of helium gas at STP.
0.030 moles He(g) x 22.4L = 0.67 L of He(g)
What is the volume of 0.05 size of Earth 1m deep in green peasmol of neon gas at STP?
0.05 mol Ne x 22.4L = 1.12L of Ne(g)
11.2L Ar(g) x 1 mole = 0.5 mole Ar(g)
1.2 mol H2O(g) x 22.4L = 26.88L of H2O
Volume at STP
x 6.02 x 1023particles
x 1 mole
6.02 x 1023 particles
x 1 mole
x molar mass
Calculate the mass, in grams (g), of the following:
3.00L of O2(g) x 1 mole x 32.00 g = 4.29 g O2(g)
b) 15 atoms of gold
15 atoms Au(s) x 1 mole x 196.97g = 4.9 x 10-21 g Au
6.02 x 1023 atoms 1 mole
Calculate the number of atoms in 2.0L of SO gas at STP3 gas.
2.0LSO3(g)x 1 mole x 6.02 x 1023 atoms = 5.3 x 1022 atoms SO3
22.4 L 1 mole
If the students in a Chemistry 20 class have gas at STP
3.25 x 105 molecules of CO2(g), how many litres do they have?
3.25 x 105molecules of CO2(g) x 1 mole = 5.40 x 10-29 mole
6.02 x 1023molecules
5.40 x 10-29mole CO2 x 22.4L = 1.21 x 10-17 L CO2