1 / 5

Calculus Section 3.7 Find higher ordered derivatives.

Calculus Section 3.7 Find higher ordered derivatives. Higher order derivative notation 1 st derivative: y’ f’(x) dy / dx D x y 2 nd derivative: y’’ f’’(x) d 2 y/dx 2 D x 2 y

aoife
Download Presentation

Calculus Section 3.7 Find higher ordered derivatives.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Calculus Section 3.7Find higher ordered derivatives. Higher order derivative notation 1st derivative: y’ f’(x) dy/dxDxy 2nd derivative: y’’ f’’(x) d2y/dx2Dx2y 3rd derivative: y’’’ f’’’(x) d3y/dx3Dx3y 4th derivative: y(4)f(4)(x) d4y/dx4Dx4y Find d4y/dx4 y = 2x6 + 3x5 – 7x4 + x3 – 5x2 + 7x - 9 Find y’’ if y = 10x5/2

  2. Find the indicated derivative. Find f’’ if f(x) = x+4 x-3 Find f’’(x) if f(x) = (3x+7)4

  3. Instantaneous acceleration is the rate of change of velocity. If s(t) is the distance function, then s’’(t) is the acceleration function. The height of a ball is given by 400 – 16t2. Find the acceleration after 2 seconds.

  4. example The distance a mouse is from its starting point is given by the function s(t) = t3 – 2t2 + 6t where s is the distance in feet and t is the time in seconds. a. Find the distance at 3 seconds. b. Find the velocity at 3 seconds. c. Find the acceleration at 3 seconds.

  5. assignment Page 157 Problems 2 – 40 even

More Related