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Equilibrium . Kinetics and Equilibrium. rate forward = k for [reactants] x and rate reverse = k rev [products] z Since rates are equal at equilibrium, k for [reactants] x = k rev [products] z K eq = [products] z [reactants] x. K’s. Kc - used when dealing with concentrations
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Kinetics and Equilibrium rate forward = kfor[reactants]x and rate reverse = krev [products]z Since rates are equal at equilibrium, kfor [reactants]x = krev [products]z Keq= [products]z [reactants]x
K’s • Kc- used when dealing with concentrations • Kp – used when dealing with partial pressures • Ka- used for acids • Kb – used for bases • Ksp – used for how soluble an ‘insoluble’ salt is
THE SIGNIFICANCE OF K K > 1means that the reaction favors the products at equilibrium Keq = [products]z [reactants]x K < 1 means that the reaction favors the reactants at equilibrium Keq= [products]z [reactants]x K = 1Keq = [products]z [reactants]x
Reaction Quotient-Q • Used if you have concentrations that may or not be equilibrium concentrations. • Can be used predict the direction the reaction will proceed to establish equilibrium. Q > K Q < K Q = K system at equilibrium Q K Shift left (toward reactants) Q K Shift right (toward products) No shift
General steps for solving equilibrium problems A. Write a balanced equation. (* do stoichiometry first in moles if needed). B. Set up equilibrium expression. C. Set up RICE diagram.
“RICE” TABLES --reaction, initial concentration, change in concentration, equilibrium concentration! Never Fails!! R = write a balanced reaction for the predominant reacting species I = fill in the initial concentrations C = what change is taking place E = equilibrium concentrations
Acids and bases • Strong – completely ionizes • Memorize (7 strong acids and the ‘b’ of strong bases • Weak –partially dissociates • If not strong, they are weak.
Buffers Solutions that resist changes in pH when either OH- or H+ ions are added. Example: NH3/NH4+ buffer system HC2H3O2 / C2H3O2- buffer system
Systems that work • weak acid + salt of weak acid • weak base + salt of weak base • weak acid + ½ # of moles of strong base • weak base + ½ # of moles of strong acid • weak acid + weak base
Conjugates • Difference of one H+ (ONLY!!)
Titration Coeff of base x M a x V a = M b X V b x coeff of acid -vol needed for equivalence point