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Calculating Percent Change in Bear's Heart Rate

Explore examples of finding percent decrease and increase in different scenarios, such as school enrollment and national park attendance, using practical equations, operations, and guided practice to enhance your understanding of percentage calculations.

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Calculating Percent Change in Bear's Heart Rate

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  1. Bears During the summer, a bear’s heart rate is about 60 beats per minute, but it can drop to as low as 8 beats per minute during the winter. What is the percent of change in a bear’s heart rate from the summer rate to the winter low rate? EXAMPLE 1 Finding a Percent of Decrease SOLUTION To find the percent of decrease, use the percent of change equation.

  2. p% = = 52 _ = 60 0.86 86.67% 60 – 8 ANSWER 60 The percent of decrease is about 86.7%. EXAMPLE 1 Finding a Percent of Decrease Write amount of decrease and divide by original amount. Subtract. Write fraction as a decimal. Write decimal as a percent.

  3. School Enrollment A school had 825 students enrolled last year. This year, 870 students are enrolled. Find the percent of increase to the nearest tenth. 870 – 825 p% = 825 45 = 825 __ 0.0545 = 5.45% EXAMPLE 2 Finding a Percent of Increase SOLUTION Write amount of increase and divide by original amount. Subtract. Write fraction as a decimal. Write decimal as a percent.

  4. ANSWER The percent of increase is about 5.5%. EXAMPLE 2 Finding a Percent of Increase

  5. National Parks From October to November one year, attendance at Everglades National Park increased about 27.4%. There were 59,084 visitors in October. To the nearest hundred, how many people visited in November? STEP 1 Find the increase. Increase 27.4%of 59,084 = = 0.274( 59,084) 16,189 EXAMPLE 3 Using Percent of Increase SOLUTION Write 27.4% as a decimal. Multiply.

  6. Add the increase to the original amount. STEP 2 New Amount 16,189 75,273 59,084 = + EXAMPLE 3 Using Percent of Increase ANSWER About 75,300people visited the park in November.

  7. 1. Original amt = 50 50 – 36 p% = 50 14 = 50 0.28 = 28% = for Examples 1, 2 and 3 GUIDED PRACTICE Tell whether the change is an increase or decrease. Then find the percent of change. Round to the nearest percent. New amt = 36 The change is a decrease since the new amount is less than the original amount Write amount of decrease and divide by original amount. Subtract. Write fraction as a decimal. Write decimal as a percent.

  8. 2. Original amt = 10 29.5 – 10 = 10 p% 19.5 = 10 1.95 = 195% = for Examples 1, 2 and 3 GUIDED PRACTICE New amt = 29.5 The change is an increase since the new amount is greater than the original amount Write amount of decrease and divide by original amount. Subtract. Write fraction as a decimal.

  9. 3. Original amt = 90 110 – 90 = 90 p% 20 = 90 0.222 = 22% = for Examples 1, 2 and 3 GUIDED PRACTICE New amt = 110 The change is an increase since the new amount is greater than the original amount Write amount of decrease and divide by original amount. Subtract. Write fraction as a decimal.

  10. 4. What If? In Example 3, suppose the attendance decreased by about 11%. Approximate, to the nearest thousand, the attendance in November decrease = 11% of 59,084 for Examples 1, 2 and 3 GUIDED PRACTICE SOLUTION Find the decrease. = 0.11(59,084) = 6499.24

  11. New amount 59,084 – 6499 52,585 ANSWER About 53,000people visited the park in November. for Examples 1, 2 and 3 GUIDED PRACTICE Subtract the decrease to the original amount.

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