1 / 8

CHAPTER 2 SECTION 6

Algebraic Proofs. CHAPTER 2 SECTION 6. Jim Smith JCHS. Properties we’ll be needing. REFLEXIVE -- a = a SYMMETRIC -- if x = 2 then 2 = x TRANSITIVE -- if a = b and b = c then a = c

abeyers
Download Presentation

CHAPTER 2 SECTION 6

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Algebraic Proofs CHAPTER 2SECTION 6 Jim Smith JCHS

  2. Properties we’ll be needing REFLEXIVE-- a = a SYMMETRIC-- if x = 2 then 2 = x TRANSITIVE-- if a = b and b = c then a = c SUBSTITUTION-- If a = b then a may be used in any equationinstead of b

  3. DISTRIBUTIVE-- a(b+c) = ab+ac ADD and SUBTRACT-- if a = b then a+c = b+c and a-c = b-c MULT and DIVIDE-- if a = b then ac = bc and a / c = b / c

  4. 2 COLUMN PROOFS Statements Reasons

  5. In An Algebraic Proof, You Must Show All Steps Used To Solve The Equation. Each Individual Step You Use Is A Statement In The Proof. You Then Give Each Statement A Reason.

  6. Given: 2x+5 = 17 Prove x = 6 Statement Reason Start by stating the given. The reason will be GIVEN 1) Given 1) 2x + 5 = 17 2) Subtraction Property 2) 2x + 5 – 5 = 17 - 5 3) 2x = 12 3) Substitution 4) 2x / 2 = 12 / 2 4) Division Property 5) X = 6 5) Substitution

  7. Remember !! • The SHOW ME steps will be Add,Sub, Mult, or Div or Distributive Properties • The DO IT steps will be Substitution

  8. Statements Reasons Given: 3x + 7 Prove: x = 3 2 = 8 • 3x + 7 = 8 1) Given • 2 • 2) 2 3x + 7 = 2 ( 8 ) 2) Mult Prop • 2 • 3x + 7 = 16 3) Substitution • 3x + 7 – 7 = 16 – 7 4) Subtraction Prop • 3x = 9 5) Substitution • 3x = 9 6) Division • 3 3 • 7) X = 3 7) Substitution

More Related