Lesson 9 - R. Chapter 9 Review. Objectives. Summarize the chapter Define the vocabulary used Complete all objectives Successfully answer any of the review exercises. Vocabulary. None new. Determine the Appropriate Confidence Interval to Construct. Which parameter are we estimating.
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Chapter 9 Review
Which parameter are we estimating
Standard Deviation, σ, or variance σ²
1) normal population
2) no outliers
1) n ≤ 0.05N
2) np(1-p) ≥ 10
yes & σ
yes & s
1) apx normal population
2) no outliers
If the sample mean is 9, which of these could reasonably be a confidence interval for the population mean?
If the population standard deviation σ = 5 and the sample size n = 25, then the margin of error for a 95% normal confidence interval is
A researcher collected 15 data points that seem to be reasonably bell shaped. Which distribution should the researcher use to calculate confidence intervals?
What issue do we have in calculatingσ / √nwhen the population standard deviation is not known?
A study is trying to determine what percentage of students drive SUVs. The population parameter to be estimated is
A study of 100 students to determine a population proportion resulted in a margin of error of 6%. If a margin of error of 2% was desired, then the study should have included
Which probability distribution is used to compute a confidence interval for the variance?
If the 90% confidence interval for the variance is (16, 36), then the 90% confidence interval for the standard deviation is
Which of the following methods are used to estimate the population mean?
A professor wishes to compute a confidence interval for the average percentage grade in the class. Which population parameter is being studied?
1: (α/2=0.005, df=18-1=17) read from table: 2.898
3: (α/2=0.025, df=22-1=21) read from table: 10.283, 35.479
8: a) n>30 large sample (σ known)b) (α/2=0.03) Z=1.88 [315.15, 334.85]c) (α/2=0.01) Z=2.326 [312.81, 337.19]d) (α/2=0.025) Z=1.96 n > 147.67
9: a) large sample size allows for x-bar to be normally distributed from a non-normal (skewed data distribution: mean vs median) b) (α/2=0.05) t=1.646 MOE=0.298 [12.702, 13.298]
15: a) x-bar = 3.244, s = 0.487 b) yes c) (α/2=0.025) [2.935, 3.553] d) (α/2=0.005) [2.807, 3.681] e) (α/2=0.005) [0.312, 1.001]
23: same because t-dist is symmetric
24: t-dist, because the tails are larger