1 / 6

EXAMPLE 2

Desk Lamp. As shown, part of the extending arm of a desk lamp is a parallelogram. The angles of the parallelogram change as the lamp is raised and lowered. Find m BCD when m ADC = 110°.

zohar
Download Presentation

EXAMPLE 2

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Desk Lamp As shown, part of the extending arm of a desk lamp is a parallelogram. The angles of the parallelogram change as the lamp is raised and lowered. Find m BCDwhen m ADC = 110°. By Theorem 8.5, the consecutive angle pairs in ABCD are supplementary. So, m ADC + m BCD = 180°. Because m ADC = 110°, m BCD =180° –110° = 70°. EXAMPLE 2 Use properties of parallelograms SOLUTION

  2. By Theorem 8 .6, the diagonals of a parallelogram bisect each other. So, Pis the midpoint of diagonals LNand OM. Use the Midpoint Formula. 4 + 0 7 7 + 0 , , 2 Coordinates of midpoint Pof OM = ( ) ( ) = 2 2 2 ANSWER The correct answer is A. Standardized Test Practice EXAMPLE 3 SOLUTION

  3. Find the indicated measure in JKLM. 3. NM By Theorem 8 .6, the diagonals of a parallelogram bisect each other. So, Nis the midpoint of diagonals KM . KN = NM 2 = NM for Examples 2 and 3 GUIDED PRACTICE SOLUTION Substitute

  4. Find the indicated measure in JKLM. 4. KM KM = KN + NM KM = KM = for Examples 2 and 3 GUIDED PRACTICE SOLUTION By theorem 8.6 2 + 2 Substitute 4 Add

  5. Find the indicated measure in JKLM. 5. m JML By Theorem 8.5, the consecutive angle pairs in JKLM are supplementary. So, m KJM + m JML = 180°. Because m KJM = 110°, m JML =180° –110° = 70°. for Examples 2 and 3 GUIDED PRACTICE SOLUTION

  6. Find the indicated measure in JKLM. 6. m KML m JML = m KMJ + m KNL 30° + m KML m KML for Examples 2 and 3 GUIDED PRACTICE SOLUTION 70° = Substitute 40° = Subtract

More Related