1 / 10

Projectile Motion

Projectile Motion. Also known as two dimensional motion or trajectory problems. Projectile Motion. Projectile motion occurs when objects are launched at an angle so they are moving in both the horizontal and vertical directions. Projectile Motion.

yazid
Download Presentation

Projectile Motion

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Projectile Motion Also known as two dimensional motion or trajectory problems

  2. Projectile Motion • Projectile motion occurs when objects are launched at an angle so they are moving in both the horizontal and vertical directions

  3. Projectile Motion • Key Idea: Because gravity only acts vertically, the way to solve these problems is to separate the problem into a vertical part and a horizontal part and solve them separately.

  4. Projectile Motion • Typically the place to start is to resolve the velocity vector (which is at an angle) into a vertical velocity and horizontal velocity.

  5. Projectile Motion • Solve the problem by keeping the vertical and horizontal components in separate tables • VerticalHorizontal • The variable which is common to both is time.

  6. Projectile Motion • Example: launch a cat at 50m/s at an angle of 30 degrees w/the horizontal • Find the maximum height, horizontal distance, and time in the air • V(horizontal) = 50 x cos(30) = 43.3 m/s • V(vertical) = 50 x sin(30) = 25 m/s

  7. Projectile Motion • Vertical • V(vertical) = 25m/s • Time (to peak) = 2.5 seconds so total time up and down is 5.0 seconds • Distance (up) = ½ a t2 = 31.2m

  8. Projectile Motion • Horizontal • We found the total time in the air = 5 seconds (from the vertical part) • The distance travelled horizontally is the horizontal velocity x time = 43.3m/s x 5s = 220m

  9. Projectile Motion • Nice visual

  10. Projectile Motion • Nicer visual

More Related