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A(not in circle) A(total ) = A(square ) – A(semicircle ) A(square ) + A(semicircle )

Half of a circle is inside a square and half is outside. If a point is selected at random inside the square, find the probability the point is not inside the circle.(Answer in terms of π ). A(not in circle) A(total ) = A(square ) – A(semicircle ) A(square ) + A(semicircle )

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A(not in circle) A(total ) = A(square ) – A(semicircle ) A(square ) + A(semicircle )

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  1. Half of a circle is inside a square and half is outside. If a point is selected at random inside the square, find the probability the point is not inside the circle.(Answer in terms of π) A(not in circle) A(total) = A(square) – A(semicircle) A(square) +A(semicircle) = (8r)2 - 1/2π(4r)2 (8r)2 + 1/2π(4r)2 = 64r2 - 1/2π (16r2) 64r2+ 1/2π (16r2) = 64r2 - 8πr2 64r2 + 8πr2 = 8r2(8 – π) 8r2(8 + π) = (8 – π) (8 + π) 4r 8r

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