CHEMISTRY 1000

1. CHEMISTRY 1000 Topic #4: Nuclear Chemistry Fall 2010 Dr. Susan Lait

2. Radioactivity and Radiation • Nuclear reactions result in changing the nuclei of atoms. These reactions are accompanied by emission of ionizing radiation (which has enough energy to excite electrons out of molecules, ‘ionizing’ them). There are three main types of ionizing radiation: • alpha rays (): helium nuclei (2 protons + 2 neutrons) • beta rays (): electrons • gamma rays (): high energy photons (higher energy than x-rays) which have no mass and no charge

3. Balancing Nuclear Reactions • In any nuclear reaction, two things are conserved: • The sum of the mass numbers of the products is equal to the sum of the mass numbers of the reactants. • The sum of the atomic numbers of the products is equal to the sum of the atomic numbers of the reactants. The “atomic number” for an electron () is considered to be -1. • The exact masses of products and reactants are not the same. The small mass difference between mass of products and reactants results in release of energy (E = mc2) and the law of conservation of energy still holds. (The law of conservation of mass is a special case of the law of conservation of energy.)

4. Balancing Nuclear Reactions • Balance the following nuclear reactions.

5. Classes of Nuclear Reactions • There are seven classes of nuclear reactions: • Alpha emission • Beta emission • Positron emission • Electron capture • Fusion • Fission • Bombardment (to make transuranium elements)

6. Classes of Nuclear Reactions * Most nuclear reactions also emit electromagnetic radiation. Emitting an  or  particle leaves the nucleus in an excited state so it emits a photon as it returns to the nuclear ground state. The energy of the photon is specific to the nuclear reaction. ** As antimatter, positrons are not directly observable. A positron is annihilated as soon as it collides with an electron, releasing  radiation (a high energy photon).

7. “nuclide” = a specific type of nucleus (i.e. containing a specific #protons and #neutrons) Classes of Nuclear Reactions • An unstable nuclide undergoes spontaneous nuclear reaction to form a more stable nuclide. If this product is also unstable, it undergoes another nuclear reaction (and another and another, etc. until a stable nuclide is reached). Such a series of alpha- and beta-emissions is called a radioactive decay series:

8. Classes of Nuclear Reactions • Some classes of nuclear reaction, on the other hand, will never occur spontaneously. Instead, they must be induced (often by hitting the nucleus with a neutron to generate a highly unstable nucleus which will then undergo the desired nuclear reaction). This is true of fission and bombardment:

9. Why Do Nuclear Reactions Occur? • What factors affect stability of a particular nuclide? • A nucleus consists of protons and neutrons held together by nuclear binding energy. • At the same time, there is electrostatic repulsion between the positively-charged protons. If this repulsion is too great, the nucleus will be unstable. • Neutrons lessen this repulsion by increasing the distance between protons; however, neutrons are inherently less stable than protons. Excess neutrons will decompose into proton/electron pairs. • It is therefore possible to make a few generalizations: • Nuclides containing more protons need more neutrons (to keep the protons apart). • Nuclides containing fewer protons need fewer neutrons (to maximize stability). • There is a maximum number of protons beyond which the nuclear binding energy cannot hold the nuclide together stably (because the electrostatic repulsion is too great).

10. Why Do Nuclear Reactions Occur? • The number of stable nuclides is relatively small. Plotting #protons (Z) vs. #neutrons (N) for all nuclides that have been made/found gives a narrow band of stable nuclides (black dots) surrounded by a wider band of unstable nuclides (red dots). The stable nuclides form the band of stability. • Nuclides farthest from the band of stability are least stable, decaying fastest. • Heavy nuclides decay faster than light ones. • N-to-Z ratio in stable nuclides is predictable: • If Z = 1-20 (H to Ca), N  Z is ideal • If Z = 20-83 (Sc to Bi), N > Z up to N  1.5 Z • If Z  84 (Po and larger), no stable nuclides exist • Even values for Z & N are conducive to stability. Almost 60% of stable nuclides have both even. Less than 2% of stable nuclides have both odd!

11. Why Do Nuclear Reactions Occur? • The type of nuclear reaction which a nuclide is most likely to undergo can be predicted from its N-to-Z ratio. • A nucleus which has “too many neutrons” (i.e. N/Z is too high) will tend to undergo beta emission. How does this improve N/Z? • A small nucleus which has “too many protons” (i.e. N/Z is too low) will tend to undergo either positron emission or electron capture. How does this improve N/Z? • A large nucleus which has “too many protons” (i.e. N/Z is too low) will tend to undergo alpha emission. How does this improve N/Z?

12. Nuclear Binding Energy • When nucleons (protons and neutrons) come together to make a nucleus, energy is released. This energy is referred to as nuclear binding energy(E) and a nuclide’s nuclear binding energy can be calculated using Einstein’s famous equation: • The nuclear binding energy for any nuclide can thus be calculated by comparing its mass to the total mass of the protons and neutrons it contains. You may have already noticed that atomic masses are not exactly equal to the sum of the masses of the protons, neutrons and electrons in the atom! • In order for a nuclide to be stable, its nuclear binding energy must be greater than the electrostatic repulsion between its protons.

13. Nuclear Binding Energy • Since they release more energy upon formation, nuclides with greater nuclear binding energies would at first seem to be more stable; however, we must also factor in the number of nucleons brought together. Otherwise, larger nuclides appear to be excessively stable are simply because they contain more nucleons. • So, a more useful quantity to calculate is the nuclear binding energy per nucleon (Eb): • where A = mass number = #nucleons = Z + N • Nuclides with larger Eb values are more stable.

14. Mproton = 1.0072765 g/mol Mneutron = 1.0086649 g/mol Melectron = 0.0005486 g/mol Nuclear Binding Energy • Calculate Eb for the helium isotopes: 3He (3.016029310 g/mol) and 4He (4.002603250 g/mol). Which isotope is more stable? For this type of calculation, ALWAYS use the mass of the specific isotope or nuclide. NEVER use the average atomic mass listed on the periodic table

15. Nuclear Binding Energy • 4He is one of the most stable nuclide. When Eb is plotted as a function of A, the most stable nuclide is found to be 56Fe: • This plot also shows which nuclides can undergo fusion (increasing Eb by increasing A) and which nuclides can undergo fission (increasing Eb by decreasing A).

16. Nuclear Binding Energy • Since a nuclear reaction involves conversion of one (or more) nucleus to another, it can be modeled as destruction of the original nucleus followed by creation of a new nucleus: • So, we can calculate the energy released by any nuclear reaction as long as we know the masses of the nuclides involved. • e.g. A neutron (1n, 1.0087 g/mol) strikes 235U (235.0439 g/mol) to give 138Xe (137.908 g/mol), 95Sr (94.913 g/mol) and 3 1n.