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EMIS 8374: Network Flows. “Easy” Integer Programming Problems: Network Flow Problems updated 4 April 2004. Basic Feasible Solutions. Standard Form. Basic Feasible Solutions. Vector-Matrix Representation. LP Formulation of Shortest Path Example. Matrix Representation.

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emis 8374 network flows

EMIS 8374: Network Flows

“Easy” Integer Programming Problems: Network Flow Problems

updated 4 April 2004

matrix representation
Matrix Representation

Observation: The last row of the matrix is equal to –1 times the sum of the other rows.

MCNF LPs always have one redundant row.

solving for the bfs
Solving for the BFS

Constraints after non-basic variables are removed:

Solution: x24 = 0, x12 = 0, x13 = 1, x35 = 1, x56 = 1

kramer s a k a cramer s rule
Kramer’s (a.k.a Cramer’s) Rule

Component j of x = A-1b is

Take the matrix A and replace

column j with the vector b.

total unimodularity
Total Unimodularity
  • A square, integer matrix is unimodular if its determinant is 1 or -1.
  • An integer matrix A is called totally unimodular (TU) if every square, nonsingular submatrix of A is unimodular.
  • From Cramer’s rule, it follows that if A is TU and b is an integer vector, then every BFS of the constraint system Ax = b is integer.
  • Examples:
    • The matrix AB from the shortest path example is TU.
    • The matrix A from the shortest path example is TU.
    • The constraint matrix for any MCNF LP is TU.
tu theorem
TU Theorem
  • An integer matrix A is TU if
    • All entries are -1, 0 or 1
    • At most two non-zero entries appear in any column
    • The rows of A can be partitioned into two disjoint sets such that
      • If a column has two entries of the same sign, their rows are in different sets.
      • If a column has two entries of different signs, their rows are in the same set.
  • The matrix A is TU if and only if is AT TU.
  • The matrix A is TU if and only if [A, I] is TU. Where I is the identity matrix.
mcnf lps are tu

Flow Balance:

A is TU, so AT is TU.