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# Probability - PowerPoint PPT Presentation

Probability. Quantitative Methods in HPELS 440:210. Agenda. Introduction Probability and the Normal Distribution Probability and the Binomial Distribution Inferential Statistics. Introduction. Recall: Inferential statistics: Sample statistic  PROBABILITY  population parameter

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### Probability

Quantitative Methods in HPELS

440:210

• Introduction

• Probability and the Normal Distribution

• Probability and the Binomial Distribution

• Inferential Statistics

• Recall:

• Inferential statistics: Sample statistic  PROBABILITY  population parameter

• Marbles Example

N = 100 marbles

50 black, 50 white

Assume:

N = 100 marbles

90 black, 10 white

What is the probability of drawing a black marble?

What is the probability of drawing a black marble?

• Using information about a population to predict the sample is the opposite of INFERENTIAL statistics

• Consider the following examples

Which jar did you PROBABLY choose your sample?

Introduction two jars

• What is probability?

• The chance of any particular outcome occurring as a fraction/proportion of all possible outcomes

• Example:

• If a hat is filled with four pieces of paper lettered A, B, C and D, what is the probability of pulling the letter A?

• p = # of “A” outcomes / # of total outcomes

• p = 1 / 4 = 0.25 or 25%

Introduction two jars

• This definition of probability assumes that the samples are obtained RANDOMLY

• A random sample has two requirements:

• Each outcome has equal chance of being selected

• Probability is constant (selection with replacement)

What is probability of drawing Jack of Diamonds from 52 card deck? Ace of spades?

What is probability of drawing Jack of Spades if you do not replace the first selection?

• Introduction

• Probability and the Normal Distribution

• Probability and the Binomial Distribution

• Inferential Statistics

Probability deck? Ace of spades? Normal Distribution

• Recall  Normal Distribution:

• Symmetrical

• Unified mean, median and mode

• Normal distribution can be defined:

• Mathematically (Figure 6.3, p 168)

• Standard deviations (Figure 6.4, 168)

With either definition, the predictability of the Normal Distribution allows you to answer PROBABILITY QUESTIONS

Probability Questions Distribution allows you to answer PROBABILITY QUESTIONS

• Example 6.2

• µ = 68 inches

•  = 6 inches

• Probability Question:

• What is the probability of selecting an adult with a height greater than 80 inches?

• p (X > 80) = ?

Probability Questions Distribution allows you to answer PROBABILITY QUESTIONS

• Example 6.2:

• Process:

• Draw a sketch:

• Compute Z-score:

• Use normal distribution to determine probability

Step 1: Draw a sketch for p(X>80) Distribution allows you to answer PROBABILITY QUESTIONS

Step 2: Compute Z-score:

Z = X - µ / 

Z = 80 – 68/6

Z = 12/6 = 2.00

Step 3: Determine probability

There is a 2.28% probability that you would select a person with a height greater than 80 inches.

Probability Questions Distribution allows you to answer PROBABILITY QUESTIONS

• What if Z-score is not 0.0, 1.0 or 2.0?

• Normal Table  Figure 6.6, p 170

Column A: Z-score Column C: Tail = smaller side Distribution allows you to answer PROBABILITY QUESTIONS

Column B: Body = larger side Column D: 0.50 – p(Z)

Using the Normal Table Distribution allows you to answer PROBABILITY QUESTIONS

• Several applications:

• Determining a probability from a specific Z-score

• Determining a Z-score from a specific probability or probabilities

• Determining a probability between two Z-scores

• Determining a raw score from a specific probability or Z-score

Determining a probability from a specific Z-score Distribution allows you to answer PROBABILITY QUESTIONS

• Process:

• Draw a sketch

• Locate the probability from normal table

• Examples: Figure 6.7, p 171

p(X > 1.00) = ? Distribution allows you to answer PROBABILITY QUESTIONS

Tail or Body?

p = 15.87%

p(X < 1.50) = ?

Tail or Body?

p = 93.32%

p(X < -0.50) = ?

p(X > 0.50) = ?

Tail or Body?

p = 30.85%

Using the Normal Table Distribution allows you to answer PROBABILITY QUESTIONS

• Several applications:

• Determining a probability from a specific Z-score

• Determining a Z-score from a specific probability or probabilities

• Determining a probability between two Z-scores

• Determining a raw score from a specific probability or Z-score

Process: Distribution allows you to answer PROBABILITY QUESTIONS

Draw a sketch

Locate Z-score from normal table

Examples: Figure 6.8a and b, p 173

Determining a Z-score from a specific probability

20% Distribution allows you to answer PROBABILITY QUESTIONS

(0.200)

20%

(0.200)

What Z-score is associated with a raw score that has 90% of the population below and 10% above?

What two Z-scores are associated with raw scores that have 60% of the population located between them and 40% located on the ends?

Column B (body)  p = 0.900

Z = 1.28

Column C (tail)  p = 0.100

Z = 1.28

Column C (tail)  p = 0.200

Z = 0.84 and -0.84

Column D (0.500 – p(Z))  0.300

Z = 0.84 and – 0.84

30%

(0.300)

30%

(0.300)

Using the Normal Table Distribution allows you to answer PROBABILITY QUESTIONS

• Several applications:

• Determining a probability from a specific Z-score

• Determining a Z-score from a specific probability or probabilities

• Determining a probability between two Z-scores

• Determining a raw score from a specific probability or Z-score

Determining a probability between two Z-scores Distribution allows you to answer PROBABILITY QUESTIONS

• Process:

• Draw a sketch

• Calculate Z-scores

• Locate probabilities normal table

• Calculate probability that falls between Z-scores

• Example: Figure 6.10, p 176

• What proportion of people drive between the speeds of 55 and 65 mph?

Step 1: Sketch Distribution allows you to answer PROBABILITY QUESTIONS

Step 2: Calculate Z-scores:

Z = X - µ /  Z = X - µ / 

Z = 55 – 58/10 Z = 65 – 58/10

Z = -0.30 Z = 0.70

Step 2: Locate probabilities

Z = -0.30 (column D) = 0.1179

Z = 0.70 (column D) = 0.2580

Step 4: Calculate probabilities between Z-scores

p = 0.1179 + 0.2580 = 0.3759

Using the Normal Table Distribution allows you to answer PROBABILITY QUESTIONS

• Several applications:

• Determining a probability from a specific Z-score

• Determining a Z-score from a specific probability or probabilities

• Determining a probability between two Z-scores

• Determining a raw score from a specific probability or Z-score

• Process:

• Draw sketch

• Locate Z-score from normal table

• Calculate raw score from Z-score equation

• Example: Figure 6.13, p 178

• What SAT score is needed to score in the top 15%?

Step 1: Sketch Z-score

Step 2: Locate Z-score

p = 0.150 (column D)

Z = 1.04

Step 3: Calculate raw score from Z-score equation

Z = X - µ /   X = µ + Z 

X = 500 + 1.04(100)

X = 604

Agenda Z-score

• Introduction

• Probability and the Normal Distribution

• Probability and the Binomial Distribution

• Inferential Statistics

Probability Z-score Binomial Distribution

• Binomial distribution?

• Literally means “two names”

• Variable measured with scale consisting of:

• Two categories or

• Two possible outcomes

• Examples:

• Coin flip

• Gender

Probability Questions Z-score Binomial Distribution

• Binomial distribution is predictable

• Probability questions are possible

• Statistical notation:

• A and B: Denote the two categories/outcomes

• p = p(A) = probability of A occurring

• q = p(B) = probability of B occurring

• Example 6.13, p 185

p = p(A) = ½ = 0.50

Tails

q = p(B) = ½ = 0.50

Tails

Each outcome has an equal chance of occurring  ¼ = 0.25

Tails

What is the probability of obtaining at least one head in 2 coin tosses?

Figure 6.19, p 186

Tails

Tails

Normal Approximation are possible? Binomial Distribution

• Binomial distribution tends to be NORMAL when “pn” and “qn” are large (>10)

• Parameters of a normal binomial distribution:

• Mean: µ = pn

• SD:  = √npq

• Therefore:

• Z = X – pn / √npq

Normal Approximation are possible? Binomial Distribution

• To maximize accuracy, use REAL LIMITS

• Recall:

• Upper and lower

• Examples: Figure 6.21, p 188

Note: The binomial distribution is a histogram, with each bar extending to its real limits

Note: The binomial distribution approximates a normal distribution under certain conditions

Normal Approximation bar extending to its real limits Binomial Distribution

• Example: 6.22, p 189

• Assume:

• Population: Psychology Department

• Males (A) = ¼ of population

• Females (B) = ¾ of population

• What is the probability of selecting 14 males in a sample (n=48)?

• p(A=14)  p(13.5<A<14.5) = ?

Normal Approximation bar extending to its real limits Binomial Distribution

• Process:

• Draw a sketch

• Confirm normality of binomial distribution

• Calculate population µ and :

• µ = pn

•  = √npq

• Calculate Z-scores for upper and lower real limits

• Locate probabilities in normal table

• Calculate probability between real limits

Step 1: Draw a sketch bar extending to its real limits

Step 2: Confirm normality

pn = 0.25(48) = 12 > 10

qn = 0.75(48) = 36 > 12

Step 3: Calculate µ and 

µ = pn  = √npq

µ = 0.25(48) = √48*0.25*0.75

µ = 12  = 3

Step 5: Locate probabilities

Z = 0.50 (column C) = 0.3085

Z = 0.83 (column C) = 0.2033

Step 4: Calculate real limit Z-scores

Z = X–pn/√npq Z = X-pn/√npq

Z = 13.5-12/3 Z = 14.5-12/3

Z = 0.50 Z = 0.83

Z = 0.50 (column C) = 0.3085 bar extending to its real limits

Z = 0.83 (column C) = 0.2033

Step 6: Calculate probability between the real limits

p = 0.3085 – 0.2033

p = 0.1052

There is a 10.52% probability of selecting 14 males from a sample of n=48 from this population

Normal Approximation bar extending to its real limits Binomial Distribution

• Example extended

• What is the probability of selecting more than 14 males in a sample (n=48)?

• p(A>14)  p(A>14.5) = ?

• Process:

• Draw a sketch

• Calculate Z-score for upper real limit

• Locate probability in normal table

Step 1: Draw a sketch bar extending to its real limits

Step 2: Calculate Z-score of upper real limit

Z = X–pn/√npq

Z = 14.5 – 12 / 3

Z = 0.83

There is a 20.33% probability of selecting more than 14 males in a sample of n=48 from this population

Step 3: Locate probability

Z = 0.83 (column C) = 0.2033

Agenda bar extending to its real limits

• Introduction

• Probability and the Normal Distribution

• Probability and the Binomial Distribution

• Inferential Statistics

Looking Ahead bar extending to its real limits Inferential Statistics

• PROBABILITY links the sample to the population  Figure 6.24, p 191

Textbook Assignment bar extending to its real limits

• Problems: 1, 3, 6, 8, 12, 15, 17, 27