Problem 36 chapter 3
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Problem 36 Chapter 3. a) Two will have disease?. b) None with Disease?. FACT(3)/(FACT(3)*FACT(0))*(Prob^0)* (1-Prob)^3 = 0.63. c) At least 1not diseased nor carrier. d) First diseased third?. (Prob^2)*(1-Prob)^1 = 0.05.

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Problem 36 Chapter 3

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Problem 36 chapter 3

Problem 36 Chapter 3


A two will have disease

a) Two will have disease?


B none with disease

b) None with Disease?

FACT(3)/(FACT(3)*FACT(0))*(Prob^0)*

(1-Prob)^3 = 0.63


C at least 1not diseased nor carrier

c) At least 1not diseased nor carrier


D first diseased third

d) First diseased third?

(Prob^2)*(1-Prob)^1 = 0.05


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