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# Problem 36 Chapter 3 - PowerPoint PPT Presentation

Problem 36 Chapter 3. a) Two will have disease?. b) None with Disease?. FACT(3)/(FACT(3)*FACT(0))*(Prob^0)* (1-Prob)^3 = 0.63. c) At least 1not diseased nor carrier. d) First diseased third?. (Prob^2)*(1-Prob)^1 = 0.05.

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## PowerPoint Slideshow about ' Problem 36 Chapter 3' - sorley

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### Problem 36 Chapter 3

FACT(3)/(FACT(3)*FACT(0))*(Prob^0)*

(1-Prob)^3 = 0.63

c) At least 1not diseased nor carrier

(Prob^2)*(1-Prob)^1 = 0.05