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Mole and # of Particles

Mole and # of Particles. A mole contains 6.02 x 10 23 particles. How many particles are in 2.0 moles of particles? 2 mol x 6.02 x 10 23 particles/mol = 12.04 x 10 23 particles = 1.2 x 10 24 particles When changing moles to number of particles simply

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Mole and # of Particles

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  1. Mole and # of Particles

  2. A mole contains 6.02 x 1023 particles. How many particles are in 2.0 moles of particles? 2 mol x 6.02 x 1023particles/mol = 12.04 x 1023 particles = 1.2 x 1024 particles When changing moles to number of particles simply Multiply the number of moles of particles by 6.02 x 1023 particles/mol

  3. A mole contains 6.02 x 1023 particles. How many particles are in 4.0 moles of particles? 4 mol x 6.02 x 1023 particles/mol = 24.08 x 1023 particles = 2.4 x 1024 particles How many particles are in 0.35 moles of particles? 0.35 mol x 6.02 x 1023 particles/mol = 2.1 x 1023 particles

  4. A mole contains 6.02 x 1023 particles. How many moles of particles are in 1.02 x 1025 particles = 1.02 x 1025 particles / 6.02 x 1023 particles/mole = 16.9 moles To change # of particles to moles simply Divide the # of particles by 6.02 x 1023 particles/mole

  5. A mole contains 6.02 x 1023 particles. How many moles of particles are in 4.74 x 1024 particles = 4.74 x 1024 particles / 6.02 x 1023 particles/mole = 7.9 moles How many moles of particles are in 3.24 x 1022 particles = 3.24 x 1022 particles / 6.02 x 1023 particles/mole = 0.054 moles

  6. A mole contains 6.02 x 1023 particles. How many particles are in 45.6 moles of particles? 44.6 moles x 6.02 x 1023 particles/mol = 24.08 x 1023 particles = 2.68 x 1025 particles How many moles are in 4.5 x 1021 particles? 4.5 x 1021 particles / 6.02 x 1023 particles/mol = 0.0075 mol

  7. How many molecules are there in 4.78 g of chlorine dioxide? ClO2 a) Find the number of moles of ClO2 first n = m / M = 4.78 g / 67 g/mol =0.0713 mol b) Now convert # of mol into particles = 0.0713 mol x 6.02 x 1023 particles/mol =4.3 x 1022 molecules of ClO2

  8. How many molecules are there in 2.3 g of aluminum bromide? AlBr3 a) Find the number of moles of AlBr3 n = m / M = 2.3 g / 267 g/mol = 0.0086 mol of AlBr3 b) Now convert # of mol into particles = 0.0086 mol x 6.02 x 1023 particles/mol = 5.2 x 1021 molecules of AlBr3

  9. What is the mass of 8.2 x 1021 molecules of C2H5? a) First find the # of moles. 8.2 x 1021 molecules / 6.02 x 1023 molecules/mol = 0.01362 mol b) Convert from moles to mass by multiplying the number of moles by the molar mass of C2H5. MM = (12 x 2 + 5 x 1 ) = 29 g/mol = (0.01362mol)x 29 g/mol = 0.395 g

  10. What is the mass of 8.2 x 1021 molecules of C2H5? a) First find the # of moles. 8.2 x 1021 molecules / 6.02 x 1023 molecules/mol b) Convert from moles to mass by multiplying the number of moles by the molar mass of C2H5. MM = (12 x 2 + 5 x 1 ) = 29 g/mol = (8.2 x 1021 molecules / 6.02 x 1023) x 29 g/mol = 0.395 g

  11. What is the mass of 3.7 x 1024 molecules of C4H10? • First find the # of moles, then find the mass. • 3.7 x 1024 molecules / 6.02 x 1023 molecules/mol • (= 6.15mol) • b) Convert from moles to mass by multiplying the number of moles by the molar mass of C4H10. • MM = (12 x 4 + 10 x 1 ) = 58 g/mol • 1 step: • (3.7 x 1024 molecules / 6.02 x 1023) x 58 g/mol = 356 g • = 3.6x102g

  12. Converting Particles, Moles and Mass 1. Find the mass of each of the following: a) 7.8 x 1026 molecules of N2O4 b) 5.6 moles of C2H5OH c) 1.56 x 1021 molecules of C3H6 d) 7.4 moles of ClS3 e) 3.6 x 1025 molecules of CO2 2. Find the number of particles in each of the following: a) 75 g of NF5 b) 0.0034 moles of C3H7OH c) 2.8 g of C5H10 d) 2.5 moles of FBr3 e) 435 g of CO2

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