'Mov eax' presentation slideshows

Lecture 13 Integer Arithmetic

Lecture 13 Integer Arithmetic. Assembly Language for Intel-Based Computers , 4th edition Kip R. Irvine. Chapter Overview. Shift and Rotate Instructions Shift and Rotate Applications Multiplication and Division Instructions Extended Addition and Subtraction

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Real Arithmetic

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Real Arithmetic

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Quiz #2 Topics

Quiz #2 Topics. Character codes Intel IA-32 architecture Registers, memory addressing Bytes, words, etc. Little-endian representation Floating-point unit Mostly MASM General form of a MASM program Directives (TITLE, INCLUDE, etc.) Segments (.code, .data, etc.)

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???? Windows ? ??????

???? Windows ? ??????. ???? ????????????????? ( ?? ). (1) ??????????. (2) ??????????. (3) ?????. (4) ??????. !?. Spybot ??. ???????????. ??????? ????. JPEG. 2005 ? 2 ?. 2004 ? 9 ?. Word ??. 2005 ? 3 ?. ??????????????????. ???? 99h ? XOR ????????

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? 6 ?

? 6 ?. ????. ? 16 ? 8086 ????????????? 32 ? 80x86 ?????????? 32 ????? 32 ????? 32 ???????. IA-32 ???????. ????? 16 ?????? 32 ?????? ????? MMX ??? SSE ??? SSE2 ???. ????? ? 16 ???????? 32 ??????. 6 .1 32 ????????. ????? ???? ?? 8086 ??. 16 ????? ?????????? 16 ?

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IA32 (Pentium) Processor Architecture

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IKI10230 Pengantar Organisasi Komputer Kuliah no. 08: Multi-module Programs

IKI10230 Pengantar Organisasi Komputer Kuliah no. 08: Multi-module Programs. Sumber : 1. Paul Carter, PC Assembly Language 2. Hamacher. Computer Organization , ed-5 3. Materi kuliah CS61C/2000 & CS152/1997, UCB. 7 April 2004

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System Programming

NFC-IET-2011. System Programming. Lecture-19 Real Time Clock Dated: June 06, 2011 By Somia Razzaq Note: Some slides and images of following lecture are taken from VU.

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Today's topics

Today's topics. Multi-dimensional arrays String processing Macros. 2-dimensional arrays. Example declaration: Matrix DWORD 5 DUP(3 DUP(?)) ; 15 elements Row major order Row index first (5 rows, 3 columns) i.e., 5 rows, 3 elements per row In HLLs, reference Matrix[0][2]

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Software attacks

Software attacks. Advanced buffer overflow: heap smashing. Heap overflow. Overflows on the heap can be exploited as well as stack overflows. void func( void* arg, int len) { char* ptr = malloc(100); memcpy(ptr, arg, len); //buffer overflow if len>100 ... }.

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Computer Architecture and Assembly Language

Computer Architecture and Assembly Language. Byte structure : a byte has 8 bits. 7. 6. 5. 4. 3. 2. 1. 0. MSB (most significant bit) LSB (least significant bit). Numeric Conversions.

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Computer Architecture and Assembly Language

Computer Architecture and Assembly Language. Data Representation Basics Bit - the basic unit of information: (true/false) or (1/0). Byte structure : a byte has 8 bits. 7. 6. 5. 4. 3. 2. 1. 0.

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Binary Context-Sensitive Recognizer (BCSR)

Binary Context-Sensitive Recognizer (BCSR). Hong Pham December 4, 2007. Motivation. Virus Signatures Database of hexadecimals Definitive registers Alter the registers and it is another signature. Register Manipulation. Different registers give different signatures. BCSR.

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The Stack and Procedures

The Stack and Procedures. Read Sections 5.4, 5.5 and 5.6 of textbook. A Process in Virtual Memory. This is how a process is placed into its virtual addressable space The code is placed at the lowest available address followed then by the data

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Assembly Programming

Practical2. Assembly Programming. Initialising Variables (Recap). Initialising variables are done in the .data section .code val1 dd 10 val2 dd 20. Initialising Variables (Recap). Val1. dd. 10. Variable Name. Variable Type. Value. Addition. This is done in the .code section

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Assembly Language Lecture 0: Introduction

Assembly Language Lecture 0: Introduction. Outline. What is Assembly Language? Why learn Assembly Language? Grade Text Book. What is Assembly Language?. Basic Microcomputer Design Instruction Execution Cycle Machine Language Assembly Language High-Level Language.

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State Machine Tool

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Exercise 1 Given the code as seen in the example, we start with the following in memory:

Exercise 1 Given the code as seen in the example, we start with the following in memory:. Addr 100h FFh FEh FDh FCh FBh FAh. STACK. ESP. 00h 61h. ESP (new). PUSH msg. ESP. Addr 100h FFh FEh FDh FCh FBh FAh. STACK. 00h 61h. We now perform: MOV AX,[ESP]

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