'1 xy' presentation slideshows

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Adopted from slides by: Andrew Davison , Computer Eng . Software Lab I I , PSU , 2014.

Functional Programming with Scheme. Adopted from slides by: Andrew Davison , Computer Eng . Software Lab I I , PSU , 2014. Overview. Constants (names) Functions Lists No-name Functions: lambda cond Recursion Higher Order Functions More on Scheme Using DrScheme.

595 views • 49 slides

Adopted from slides by: Andrew Davison , Computer Eng . Software Lab I I , PSU , 2014.

Functional Programming with Scheme. Adopted from slides by: Andrew Davison , Computer Eng . Software Lab I I , PSU , 2014. Overview. Constants (names) Functions Lists No-name Functions: lambda cond Recursion Higher Order Functions More on Scheme Using DrScheme.

556 views • 49 slides

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?????. ?????????????? ???? ?????????. ??? (list) ??? (structure) ??????. ????????? ???????????? ??????????????? ???????? ??? ?????????. ??????????. Carl (1926) green. Bettina (1926) green. Adam (1950) yeloow. Dave(1955) black. Eva (1965) blue. Fred (1966) pink. Gustav (1988) brown.

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??? ???????. A. L 2. 1 ??????? (1) ????????????????? ????????????????????????????????????????? AB?L 1 ? L 2 ?L 1 ? ?? AP ? AB ?? A ?????????? P ? AP ? L 1 ????. Q. P ?. L 1. P. B. Q=?BAP? ? /2 AP ? L 2 ??? L 1 ???? P ? ??? L 2 ? L 1 ??????? ???? ?

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Topics: Significance Testing of Correlation Coefficients

Topics: Significance Testing of Correlation Coefficients. Inference about a population correlation coefficient: Testing H 0 : ? xy = 0 or some specific value Testing H 0 : ? xy = 0 for two or more correlations based on the same sample

454 views • 17 slides

2004 PSAT Corrections - Math 4

2004 PSAT Corrections - Math 4. In the figure, which of the following line segments has a slope of 2? A. PA B. PB C. PC D. PD E. PE. 59%. This slopes UP 2 and over 1. B. C. D. E. PD goes up 5 and over 1. PB slopes down instead of up. A. P. PA slopes down instead of up.

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Mechanism (FKN model)

Mechanism (FKN model). J. Chem. Phys. 131 , 104512 (2009). FKN model details. A(R2) X + Y + H + ? 2P k 1 = 2 ? 10 6 h , M -1 s -1 (1) A(R3) Y + A + 2H + ? X + P k 2 = 2 h 2 a , s -1 (2) B(R4) X + X ? P k 3 = 3000, M -1 s -1 (3)

304 views • 3 slides