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Physics 2 for Electrical Engineering

Ben Gurion University of the Negev. www.bgu.ac.il/atomchip , www.bgu.ac.il/nanocenter. Physics 2 for Electrical Engineering. Lecturers: Daniel Rohrlich , Ron Folman Teaching Assistants: Ben Yellin, Yoav Etzioni Grader: Gady Afek.

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Physics 2 for Electrical Engineering

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  1. Ben Gurion University of the Negev www.bgu.ac.il/atomchip,www.bgu.ac.il/nanocenter Physics 2 for Electrical Engineering Lecturers: Daniel Rohrlich , Ron Folman Teaching Assistants: Ben Yellin, Yoav Etzioni Grader: Gady Afek Week 8. Faraday’s law – Magnetism in matter • Faraday’s law of induction • Lenz’s law • “motional emf” • towards Maxwell’s equations Sources: Halliday, Resnick and Krane, 5th Edition, Chaps. 34-35.

  2. Magnetism in matter We classify materials as diamagnetic, paramagnetic or ferromagnetic according to their magnetic properties. These three classes of materials differ in their behavior in a magnetic field.

  3. Magnetism in matter We classify materials as diamagnetic, paramagnetic or ferromagnetic according to their magnetic properties. These three classes of materials differ in their behavior in a magnetic field. When a diamagnetic material is placed in a magnetic field, it generates a weak field in the opposite direction. In this sense, its behavior is analogous to a dielectric material. When a paramagnetic material is placed in a magnetic field, it generates a weak field in the same direction. Ferromagnetic materials, unlike diamagnets and paramagnets, may stay magnetized when taken out of a magnetic field.

  4. Magnetism in matter For diamagnetic and paramagnetic materials, the induced field is proportional to the applied field; the proportionality constant is called the magnetic susceptibility and denoted by the letter χ. In an applied field B, the material generates a field χB and the total field inside the material is B + χB. χfor some diamagnetic and paramagnetic materials at 300 K Paramagnetic χDiamagnetic χ

  5. Magnetism in matter A current in an empty solenoid creates a magnetic field B. What happens to B if we fill the solenoid with (a) aluminum or (b) copper? χfor some diamagnetic and paramagnetic materials at 300 K Paramagnetic χDiamagnetic χ

  6. Magnetism in matter • It is conventional to define two more vector fields, the magnetic field H and the magnetizationM, as follows: • μ0H is the magnetic field in vacuum due to currents. • μ0M is the magnetic field generated by a diamagnetic or paramagnetic material. • We have defined the magnetic susceptibility by μ0M = χB = χ(μ0H). Therefore the effective B inside a diamagnetic or paramagnetic material is • B + χB = μ0H + χ(μ0H) = μ0(1 +χ)H = μH , • where μ = μ0(1 +χ) is the magnetic permeability of a material.

  7. Magnetism in matter • Rank the following: • μ0 • μ for a paramagnet • μ for a diamagnet

  8. B B – – Magnetism in matter A qualitative explanation of diamagnetism: In some atoms, electrons are paired so that the total magnetic moment of the atom is zero. The electrons orbit the nucleus in opposite directions, hence their magnetic dipole moments cancel. But as we saw in Lecture 6 on the Lorentz force, Slides 47, 48 and 49, an external magnetic field Bdecreases the cyclotron frequency ω of one electron and increasesω of the other. ω increases ω decreases

  9. B B – – Magnetism in matter A qualitative explanation of diamagnetism: In some atoms, electrons are paired so that the total magnetic moment of the atom is zero. The electrons orbit the nucleus in opposite directions, hence their magnetic dipole moments cancel. The result is a slight magnetic dipole moment opposite to B! ω increases ω decreases

  10. Magnetism in matter Living beings are diamagnets because water is diamagnetic. Frog levitation

  11. Magnetism in matter A qualitative explanation of paramagnetism: Some atoms have permanent magnetic moments that interact only weakly with each other and their orientation is random. But in an external magnetic field, the atomic moments tend to line up with the field, though thermal motion may still scatter their orientations. Some ferromagnetic materials become paramagnetic above a critical temperature called the Curie temperature, named after Pierre Curie.

  12. Magnetism in matter A qualitative explanation of paramagnetism: Some atoms have permanent magnetic moments that interact only weakly with each other and their orientation is random. But in an external magnetic field, the atomic moments tend to line up with the field, though thermal motion may still scatter their orientations. This explanation sounds a lot like what happens to a dielectric material in a capacitor. Why does a dielectric decrease E while a paramagnetic increases B? E ≠ 0 E = 0

  13. Magnetism in matter A qualitative explanation of paramagnetism: Some atoms have permanent magnetic moments that interact only weakly with each other and their orientation is random. But in an external magnetic field, the atomic moments tend to line up with the field, though thermal motion may still scatter their orientations. Answer: A magnetic dipole μ tends to line up with B just as an electric dipole p tends to line up with E. But pdecreases E and μincreases B. E ≠ 0 E = 0

  14. 4 4 2 2 IBa θ θ 3 B IBa Torque on a current loopREVIEW Whenever moves to the right of , the torque switches direction. The area vector A always tends to line up with B. Defining the magnetic dipole moment of the current loop to be μ = IA, we can write τ= μ × B. This is a slide from Lecture 6 on the Lorentz force. Note, if we line up these current loops, they will behave like solenoids with their magnetic fields parallel to B. A

  15. Magnetism in matter Sinceμ increases B, a diamagnetic material (which has μ antiparallel to B) tends to decrease B while a paramagnetic material (which has μ parallel to B) tends to increase B, as stated.

  16. Magnetism in matter The liquid oxygen in this photograph is suspended between the poles of a magnet. Is liquid oxygen a diamagnetic or a paramagnetic material?

  17. 4 2 2 IBa A θ θ 3 B 4 IBa Torque on a current loopREVIEW Whenever moves to the right of , the torque switches direction. The area vector A always tends to line up with B. If we integrate τdθ' starting from θ' = 0, we get the work due to the magnetic torque: so the potential energy U of a magnetic dipole μin a field B is U = –μ · B. This slide from Lecture 6 shows that U = –μ · B.

  18. Magnetism in matter The liquid oxygen in this photograph is suspended between the poles of a magnet. So is liquid oxygen a diamagnetic or a paramagnetic material? Answer: If liquid oxygen were diamagnetic, μ · B would be negative; then U = –μ · B would be minimized by small B and the liquid would go to where the B field is weakest. No, liquid oxygen is paramagnetic! μ · B is positive, hence U = –μ · B is minimized by large B and the liquid goes to where B is strongest, i.e. between the poles.

  19. Magnetism in matter The response of a ferromagnetic material to B is not linear. Therefore the magnetic susceptibility χ is not defined for a ferromagnetic material such as iron, although B = μH is still in use. Every ferromagnetic material divides into magnetized domains of volume 10–12 – 10–8 m3, each containing 1017 – 1021 atoms.

  20. Magnetism in matter Every ferromagnetic material divides into magnetized domains of volume 10–12 – 10–8 m3, each containing 1017 – 1021 atoms. Experiments show that, in an external magnetic field, domains parallel to the external field grow larger at the expense of the other domains. The material may remain magnetized when the external field is turned off. This effect is called hysteresis. B

  21. B Start Increasing Bapp Bapp Decreasing Bapp Magnetism in matter Hysteresis curve of ferromagnetism: Bapp is the applied field, B is the resultant field.

  22. B Start Increasing Bapp Bapp Decreasing Bapp Magnetism in matter This “memory” of ferromagnetic materials is the basis for magnetic memory in audio and video tapes, and magnetic computer disks!

  23. Faraday’s law of induction In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current! Source: UCSC

  24. Faraday’s law of induction In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current! The sign of the current depends on the sign of dΦB/dt.

  25. Faraday’s law of induction In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current! The sign of the current depends on the sign of dΦB/dt.

  26. Faraday’s law of induction In 1831, Michael Faraday (in England) and Joseph Henry (in the U.S.) independently discovered that a changing magnetic flux ΦB through a conducting circuit induces a current! The sign of the current depends on the sign of dΦB/dt.

  27. Faraday’s law of induction In fact, the induced “emf” E is directly proportional to dΦB/dt. What is an “emf”? It is short for “electromotive force”, which is not the correct term because an “emf” is not a force. It has units of volts. An “emf” is like a potential, but here, evidently, the concept of a potential doesn’t work. Physically, an “emf” is an electric field that is created in a conductor. A better version of Faraday’s law is

  28. Faraday’s law of induction Example 1: A conducting circuit wound 200 times has a total resistance of 2.0 Ω. Each winding is a square of side 18 cm. A uniform magnetic field B is directed perpendicular to the plane of the circuit. If the field changes linearly from 0.00 to 0.50 T in 0.80 s, what is the magnitude of (a) the induced “emf” E in the circuit (b) the induced electric field E, and (c)the induced current I?

  29. Faraday’s law of induction Example 1: A conducting circuit wound 200 times has a total resistance of 2.0 Ω. Each winding is a square of side 18 cm. A uniform magnetic field B is directed perpendicular to the plane of the circuit. If the field changes linearly from 0.00 to 0.50 T in 0.80 s, what is the magnitude of (a) the induced “emf” E in the circuit (b) the induced electric field E, and (c)the induced current I? Answer: (a) We calculate dΦB/dt = (dB/dt) (200) (area)= (0.625T/s) (200) (18 cm)2 = 4.05 T · m2/s = 4.05 W/s = 4.05 V = E. (The weber W = T · m2 is the MKS/SI unit of magnetic flux, and since T = N /(m/s) · C = V · s/m2, we have W/s = V.)

  30. Faraday’s law of induction Example 1: A conducting circuit wound 200 times has a total resistance of 2.0 Ω. Each winding is a square of side 18 cm. A uniform magnetic field B is directed perpendicular to the plane of the circuit. If the field changes linearly from 0.00 to 0.50 T in 0.80 s, what is the magnitude of (a) the induced “emf” E in the circuit (b) the induced electric field E, and (c)the induced current I? Answer: (b) The total length of the wire is (200) (4) (0.18 m) = 144 m. From the “emf” = 4.05 V we infer E = 4.05 V/144 m = 0.028 V/m. (c) The current is I = V/R = 4.05 V/2.0 Ω = 2.0 A.

  31. Bulb 1 Bulb 2 B Faraday’s law of induction Example 2: Two bulbs are connected to opposite sides of a loop of wire, as shown. A decreasing magnetic field (confined to the circular area shown) induces an “emf” in the loop that causes the two bulbs to light. What happens to the brightness of each bulb when the switch is closed?

  32. Bulb 1 Bulb 2 B Faraday’s law of induction Answer: Bulb 2 stops glowing, since it is shorted out, and Bulb 1 glows brighter, since it is the only resistance in the circuit.

  33. v FB R L Fapp I x Faraday’s law of induction Example 3: The conducting bar at the right is pulled right with force Fapp at speed v. The resistance R is the only resistance in the circuit. The magnetic field B is constant and perpendicular to the plane of the circuit. What is the current I and what is the power applied?

  34. v FB R L Fapp I x Faraday’s law of induction Answer: The flux ΦB is BLx, so dΦB/dt = BLv. Thus the current is I = (BLv)/R. The force FB equals BIL so the power applied is FBv = BILv =I2R, i.e. the power applied is the power lost in “Joule heating” of the resistor.

  35. v FB R L Fapp I x Lenz’s law Let’s see if we can understand not only the magnitude but also the sign of the current induced by a changing magnetic field. The figure below is taken from Example 3 with one change: The direction of the induced current I is reversed.

  36. Lenz’s law But if the direction of I is reversed, then so is the direction of FB; then the bar accelerates to the right, v increases, I increases, FB increases further without limit, and energy is not conserved. v FB R L Fapp I x

  37. Lenz’s law But if the direction of I is reversed, then so is the direction of FB; then the bar accelerates to the right, v increases, I increases, FB increases further without limit, and energy is not conserved. v FB R L I x

  38. Lenz’s law But if the direction of I is reversed, then so is the direction of FB; then the bar accelerates to the right, v increases, I increases, FB increases further without limit, and energy is not conserved. Consider also the direction of the magnetic flux generated by I. v FB R L I x

  39. v FB R L Fapp I x Lenz’s law These considerations lead us to conclude, with H. Lenz, that the current induced in a loop by a changing magnetic flux must generate an opposite magnetic flux through the loop.

  40. B B – – Lenz’s law Example 1: If we look back at the qualitative explanation of diamagnetism, we see that electrons in atomic orbits are just obeying Lenz’s law. ω increases ω decreases

  41. Lenz’s law Example 2: The galvanometer indicates a clockwise current (seen from above). The south pole of the magnet is down. Is the hand inserting or withdrawing the magnet?

  42. S N Lenz’s law Example 2: The galvanometer indicates a clockwise current (seen from above). The south pole of the magnet is down. Is the hand inserting or withdrawing the magnet? Answer: A clockwise current implies a downward magnetic flux. So the flux due to the magnet must be increasing. The flux from the south pole of a magnet increases when the magnet is inserted.

  43. Lenz’s law Example 3: A cylindrical magnet of mass M fits neatly into a very long metal tube with thin steel walls, and slides down it without friction. The radius of the magnet is r and the strength of the magnetic field at its top and bottom is B. The magnet begins falling with acceleration g. (a) Show that the speed of the magnet approaches a limiting value v. (b) What is the rate of heat dissipation in the tube, in terms of v and the other data?

  44. Lenz’s law Answer: (a) The falling magnet induces a circulating current in the tube. By Lenz’s law, the magnetic field of this current opposes the falling magnet, until the magnetic force exactly balances the force of gravity on the magnet, which falls with constant speed v. (b) Gravity, the only external force on this system, does work at the rate Mgv. By energy conservation, this must be the rate of heat dissipation in the tube.

  45. “Motional emf” A so-called “motional emf” arises when a conductor moves in a constant magnetic field. Thus the moving bar (below) is an example of a “motional emf”. But a “motional emf” can arise also from the Lorentz force without any magnetic induction. v FB R L Fapp I x

  46. B + + L v FB – – “Motional emf” Example 1: A conducting strip of length L moves sideways with constant velocity v through a constant B pointing out of the screen. What is the potential difference ΔV between the two ends of the strip?

  47. B + + L v FB – – “Motional emf” Answer: At equilibrium, the force on charges anywhere in the strip must vanish, i.e. E = vB as in Hall effect. The potential difference is then ΔV = EL = vBL.

  48. v r dr L O “Motional emf” Example 2: A conducting strip of length L rotates around a point O with constant angular frequency ω, in a constant B pointing out of the screen. What is the potential difference ΔV between the two ends of the strip?

  49. v r dr L O “Motional emf” Answer: An electron in an element dr of the conducting strip is subject to a centripetal magnetic force evB which must be balanced by an electric force eE = evB = eωrB. (Note vis not uniform along the strip.) Integrating E(r)dr along the strip, we obtain

  50. Towards Maxwell’s equations The set of four fundamental equations for E and B, together with the Lorentz force law FEM = q (E + v × B), sum up everything we have learned so far about electromagnetism! (Gauss’s law) (Faraday’s law) (Ampère’s law)

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